将C代码转换为MIPS迭代阶乘函数

ble $t2, $t4, end_loop #i<=k, end the loop

不,C的第二部分 for 循环,而不是结束它。

你在这里做的事不公平 $t1 和 $t2

您可能想要使用 bgt 而不是 ble

您的循环条件 ble $t2, $t4, end_loop #i<=k, end the loop 将结束循环,如果 i<=k

正如在下面代码的注释中所说,我已经实现了一个 do {...} while (); 这不是OP所要求的。然而,代码可以工作。在笔划文本下方是真正的答案( for

end_loop: 标记并跳转到 loop: 标签带有 ble

fac:
    move $t4, $t0 #$t0 is the input from the user and $t4 is k in the C code
    li $t1, 1 #$t1 is f in the C code, initialising it to 1
    li $t2, 1 #$t2 is i in the C code, declaring it as 1
    loop:
    mul $t1, $t1, $t2 #f=f*i
    addi $t2, $t2, 1
    ble $t2, $t4, loop #i<=k, loop goes on if not this doesn't jump

要实现您要求的for循环,您需要更改 ble公司 ( <=

ble $t2, $t4, end_loop #i<=k, end the loop

到 bgt >

bgt $t2, $t4, end_loop #i>k, end the loop