我正在尝试设置我的网站,以便我的工作详细信息的url将使用slug字段而不是pk。它告诉我用给定的slug(是一个int,147)它找不到我的工作。

更新:

在查看DetailView描述后 https://ccbv.co.uk/projects/Django/1.11/django.views.generic.detail/DetailView/ 我意识到有一个 slug_field 的属性 DetailView . 我的新视图如下所示:

class JobDetailView(CacheMixin, DetailView):
    model = Job
    slug_field = 'slug'

问题:

URL:

urlpatterns = [
    url(r'^careers$', views.job_list, name='job-list'),
    url(r'^careers/(?P<slug>[0-9]+)/$', views.JobDetailView.as_view(), name='job-detail'),
]

查看:

class JobDetailView(CacheMixin, DetailView):
    model = Job
    pk_url_kwarg = 'slug'
    def get_object(self, *args, **kwargs):
        # Call the superclass
        object = super(JobDetailView, self).get_object()
        # Return the object
        return object

    def get(self, request, *args, **kwargs):
        object = super(JobDetailView, self).get(request, *args, **kwargs)
        return object

型号:

class Job(UpdateAble, PublishAble, models.Model):
    slug = models.CharField(unique=True, max_length=25)
    facility = models.ForeignKey('Facility')
    recruiter = models.ForeignKey('Recruiter')
    title = models.TextField()
    practice_description = models.TextField(blank=True, default="")
    public_description = models.TextField(blank=True, default="")

    objects = JobManager()

    def get_next(self, **kwargs):
        jobs = Job.objects.published()
        next = next_in_order(self, qs=jobs)
        if not next:
            next = jobs[0]
        return next

    def get_prev(self, **kwargs):
        jobs = Job.objects.published()
        prev = prev_in_order(self, qs=jobs)
        if not prev:
            prev = jobs[len(jobs)-1]
        return prev

    def __str__(self):
        return f'{self.facility}; {self.title}'

经理:

class JobManager(models.Manager):

    def published(self):
        return super(JobManager, self).get_queryset().filter(is_published=True).order_by('facility__name', 'title')