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颁发提供程序凭据之前的Oauth令牌请求

signpost launchpad oauth rest java

SyCode · 技术社区 · 9 年前

如果我问了一些愚蠢的问题,请原谅我,我是这里的新手。我需要在Java应用程序中实现OAuth,以便根据启动板进行身份验证。net API。这个 documentation 使用三个参数指定令牌请求的启动:oauth_consumer_key例如(我的应用程序的名称)、oauth_signature_method例如“PLAINTEXT”和oauth_sgnature例如字符串“&”。我意识到大多数OAuth库都需要我已经从中获取了消费者密钥和消费者Id/密码 OAuth提供者(例如在Twitter上发布的),大多数示例都是以这种方式组织的。然而,发射台。net仅在发出请求令牌后才发出这些参数(它们不使用第三方提供者)。我如何继续?我目前在尝试了一些抛出错误的库之后陷入了困境。非常感谢您提供的有用信息。官方的launchpad库在python中。

我的初始代码如下:

public class Quicky {

    public static void main(String[] args) throws Exception {
        CloseableHttpClient httpclient = HttpClients.createDefault();
        try {
            HttpGet httpGet = new HttpGet("https://launchpad.net/+request-token");
            CloseableHttpResponse response1 = httpclient.execute(httpGet);
try {
                System.out.println("Your current GET request status:" + response1.getStatusLine());
                HttpEntity entity1 = response1.getEntity();
  EntityUtils.consume(entity1);
            } finally {
                response1.close();
            }

            HttpRequest request;
            HttpPost httpPost = new HttpPost("https://launchpad.net/+request-token");
            PostMethod poster = new PostMethod();
            List <NameValuePair> postParams = new ArrayList <NameValuePair>();
            postParams.add(new BasicNameValuePair("oauth_customer_key", "XXXX"));
            postParams.add(new BasicNameValuePair("oauth_signature_method", "PLAINTEXT"));
            postParams.add(new BasicNameValuePair("oauth_signature", "&"));
   httpPost.setEntity(new UrlEncodedFormEntity(postParams, "utf-8"));
//            httpPost.setEntity(entity1);
            httpclient.execute(httpPost);

            HttpParameters requestParams = (HttpParameters) postParams;
            CloseableHttpResponse response2 = httpclient.execute(httpPost);
            try {
                System.out.println("Your current POST request status:" + response2.getStatusLine());
                HttpEntity entity2 = response2.getEntity();
                // do something useful with the response body
                // and ensure it is fully consumed
                EntityUtils.consume(entity2);
            } finally {
                response2.close();
            }
        } finally {
            httpclient.close();
        }
    }

}

1 回复 | 直到 9 年前

SyCode 9 年前

经过一些研究和代码重构,我终于解决了问题错误消息。正确的代码在下面,也许它对外面的人有用。

    public class LaunchPadTokenRetriever {  

   public static void main(String[] args) throws ClientProtocolException,       IOException{

    CloseableHttpClient httpclient = HttpClients.createDefault();

    HttpPost httpPost = new HttpPost("https://launchpad.net/+request-token");
    httpPost.addHeader("Content-Type", "application/x-www-form-urlencoded");

    List <NameValuePair> urlParams = new ArrayList <NameValuePair>();
    urlParams.add(new BasicNameValuePair("oauth_signature", "&"));
    urlParams.add(new BasicNameValuePair("oauth_consumer_key", "tester"));
    urlParams.add(new BasicNameValuePair("oauth_signature_method", "PLAINTEXT"));
    httpPost.setEntity(new UrlEncodedFormEntity(urlParams));
    CloseableHttpResponse response = httpclient.execute(httpPost);
    System.out.println(response);

    try {
      System.out.println(response.getStatusLine());
      HttpEntity entity = response.getEntity();
      ResponseHandler<String> responseHandler = new BasicResponseHandler();
      String responseBody =  httpclient.execute(httpPost, responseHandler);
      System.out.println("Initial credentials ---> "+ responseBody);
      System.out.println();    
      String getresponse = responseBody;

      EntityUtils.consume(entity);
    } finally {
      response.close();
    }
  }

}