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字典、列表和字符串

dictionary list string python-3.x python

FÄÅ ÛÅ · 技术社区 · 2 年前

词典 ,它以并将其拆分为单个串所以词典

我知道有一种方法可以简化代码并使其大大缩小,但我不知道如何实现。

也许我应该用在里面变量 len()

是的,我是编程新手。

提前感谢!

decoder = {
"96": "0",
"97": "1",
"98": "2",
"99": "3",
"100": "4",
"101": "5",
"102": "6",
"103": "7",
"104": "8",
"105": "9",
}
test = list(str(num) for num in 
input("Enter the list items 
separated by space: 
").strip().split()).
length = len(test)
if length == 1:
    a, = test
    print(decoder[a])
elif length == 2:
    a, b = test
    print(decoder[a])
    print(decoder[b])
elif length == 3:
    a, b, c = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
elif length == 4:
    a, b, c, d = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
elif length == 5:
    a, b, c, d, e = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
elif length == 6:
    a, b, c, d, e, f = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
    print(decoder[f])
elif length == 7:
    a, b, c, d, e, f, g = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
    print(decoder[f])
    print(decoder[g])
elif length == 8:
    a, b, c, d, e, f, g, h = test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
    print(decoder[f])
    print(decoder[g])
    print(decoder[h])
elif length == 9:
    a, b, c, d, e, f, g, h, i = 
    test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
    print(decoder[f])
    print(decoder[g])
    print(decoder[h])
    print(decoder[i])
elif length == 10:
    a, b, c, d, e, f, g, h, i, j = 
    test
    print(decoder[a])
    print(decoder[b])
    print(decoder[c])
    print(decoder[d])
    print(decoder[e])
    print(decoder[f])
    print(decoder[g])
    print(decoder[h])
    print(decoder[i])
    print(decoder[j])

2 回复 | 直到 2 年前

Ignatius Reilly 2 年前

您可以在中使用,与使用输入项创建列表相同,并使用for循环迭代这些项:

decoder = {
"96": "0",
"97": "1",
"98": "2",
"99": "3",
"100": "4",
"101": "5",
"102": "6",
"103": "7",
"104": "8",
"105": "9",
}

test = [str(num) for num in input("Enter the list items separated by space: ").strip().split()]

for item in test:
    print(decoder[item])

另外,请注意我是如何定义的 test 使用列表理解:)

Seth Speaks 2 年前

这将帮助您处理解码器中没有的密钥。

decoder = {
"96": "0",
"97": "1",
"98": "2",
"99": "3",
"100": "4",
"101": "5",
"102": "6",
"103": "7",
"104": "8",
"105": "9",
}
test = list(str(num) for num in input("Enter the list items separated by space: ").strip().split())
for num in test:
    try:
        print(decoder[num])
    except KeyError:
        print(f"Num {num} is not in the decoder")