如何嵌套numba jitclass

我试图理解@jitclass装饰器如何与嵌套类一起工作。我写了两个虚拟类:fifi和toto fifi具有toto属性。这两个类都有@jitclass修饰符,但编译失败。代码如下:

菲菲公司

from numba import jitclass, float64
from toto import toto

spec = [('a',float64),('b',float64),('c',toto)]

@jitclass(spec)
class fifi(object):
  def __init__(self, combis):
    self.a = combis
    self.b = 2
    self.c = toto(combis)

  def mySqrt(self,x):
    s = x
    for i in xrange(self.a):
      s = (s + x/s) / 2.0
    return s

toto.py(总计):

from numba import jitclass,int32

spec = [('n',int32)]

@jitclass(spec)
class toto(object):
  def __init__(self,n):
    self.n = 42 + n

  def work(self,y):
    return y + self.n

启动代码的脚本:

from datetime import datetime
from fifi import fifi
from numba import jit

@jit(nopython = True)
def run(n,results):
  for i in xrange(n):
    q = fifi(200)
    results[i+1] = q.mySqrt(i + 1)

if __name__ == '__main__':
  n = int(1e6)
  results = [0.0] * (n+1)
  starttime = datetime.now()
  run(n,results)
  endtime = datetime.now()

  print("Script running time: %s"%str(endtime-starttime))
  print("Sqrt of 144 is %f"%results[145])

当我运行脚本时,我得到[…]

键入错误:未键入全局名称“toto” 文件“fifi.py”,第11行

请注意,如果我在“fifi”中删除了对“toto”的引用,代码就可以正常工作了,多亏了numba,我得到了x16的速度提升。