如果在检查类型时重写显式运算符,为什么不考虑is运算符?

考虑以下代码示例:

public class Human {    
    public string Value { get; set;}
}
public class Car { 

    public static explicit operator Human (Car c) { 

        Human h = new Human();

        h.Value = "Value from Car";
        return h;
    }
}

public class Program { 
public static void Mani() { 
        Car c = new Car();

        Human h = (Human)c;
        Console.WriteLine("h.Value = {0}", h.Value);
        Console.WriteLine(c is Human);
}
}

向上我提供了一个从汽车到人类的显式转换的可能性,尽管汽车和人类的层次结构是不相关的!上面的代码仅仅意味着 “汽车可以改装成人”

但是,如果运行代码段,您将找到表达式 c is Human 计算结果为假! I used to believe that the is operator is kinda expensive cause it attempts to do an actual cast InvalidCastException . 如果操作符尝试强制转换,那么强制转换应该成功,因为有一个操作符逻辑应该执行强制转换!

是否测试层次结构 “是-a”
“可转换为” a型?