按差异对元素排序

我们可以根据你提供的工作。

people = [(25, 10000), (45, 22000), (20, 11000), (26, 13000), (27, 11000)]

people_by_age = sorted(people, key = lambda t: (t[0], t[1]))
# [(20, 11000), (25, 10000), (26, 13000), (27, 11000), (45, 22000)]

N = len(people_by_age)

for i,_ in enumerate(people_by_age):

    # For all but the last person.
    if i+1 < N:

        # If the current and next persons have a close age.
        if abs(people_by_age[i][0] - people_by_age[i+1][0]) <= 2: 

            # Swap their position in the list based on income.
            if people_by_age[i][1] < people_by_age[i+1][1]:
                temp = people_by_age[i]
                people_by_age[i] = people_by_age[i+1]
                people_by_age[i+1] = temp

print(people_by_age) # by age and income.
# [(20, 11000), (26, 13000), (27, 11000), (25, 10000), (45, 22000)]

i+1<N 这很烦人,您还可以编写代码,这样它就会忽略我们最后得到的索引器。不过,这有点不太明确。

for i,_ in enumerate(people_by_age):

    try:      
        ...        
    except IndexError:
        break