从数组中提取模式和后续n个元素,并计算出现次数

假设您对单元阵列输出很满意,那么这很好:

C = [1 2 3 4 0 3 2 5 6 7 1 2 3 4 150 30 42 1 2 3 4 0 3]
p = [1 2 3 4]
n = 2

% full patttern length - 1
dn = numel(p) + n - 1

%// find indices
ind = strfind(C,p)

%// pre check if pattern at end of array
if ind(end)+ dn  > numel(C), k = -1; else k = 0; end

%// extracting
temp = arrayfun(@(x) C(x:x+dn), ind(1:end+k) , 'uni', 0)

%// post processing
[out, ~, idx] = unique(vertcat(temp{:}),'rows','stable')
occ = histcounts(idx).'

如果阵列 C 以至少结束 n 图案最后一次出现后的元素 p ,您可以使用缩写形式:

out = arrayfun(@(x) C(x:x+n+numel(p)-1), strfind(C,p) , 'uni', 0)

out =

     1     2     3     4     0     3
     1     2     3     4   150    30

occ =

     2
     1

一个简单的解决方案可以是:

C = [1 2 3 4 0 3 2 5 6 7 1 2 3 4 150 30];
pattern = [1 2 3 4];
numberOfAddition = 2;
outputs = zeros(length(A),length(pattern)+ numberOfAddition); % preallocation
numberOfFoundPattern =  1;
lengthOfConsider = length(C) - length(pattern) - numberOfAddition;
for i = 1:lengthOfConsider 
     if(sum(C(i:i+length(pattern)) - pattern) == 0) % find pattern
         outputs(numberOfFoundPattern,:) = C(i:i+length(pattern)+numberOfAddition);
         numberOfFoundPattern = numberOfFoundPattern + 1;
     end
end
outputs = outputs(1:numberOfFoundPattern - 1,:);