在联接表中搜索

根据外键将它们全部连接起来,按您感兴趣的菜系表的所有列进行筛选。

SELECT cuisine.id, cuisine.name
  FROM cuisine
  INNER JOIN recipe on recipe.cuisine_id = cuisine.id
  INNER JOIN ingredients_recipes ir ON ir.recipe_id = recipe.id
  INNER JOIN ingredients on ingredients.id = ir.ingredient_id
  WHERE ingredients.name = 'Tomatoe'
  GROUP BY cuisine.id, cuisine.name

你可以试试 INNER JOIN 将所有四个表合并,如下例所示:

SELECT      DISTINCT c.name
FROM        cuisines AS c
INNER JOIN  recipes AS r ON (r.cuisine_id = c.id)
INNER JOIN  ingredients_recipes AS ir ON (ir.recipe_id = r.id)
INNER JOIN  ingredients AS i ON (i.id = ir.ingredient_id)
WHERE       i.name = 'tomatoes';

SELECT name
FROM cuisines
WHERE id IN (
    SELECT cuisine_id 
    FROM recipes r 
    JOIN ingredients_recipes ir ON r.id = ir.recipe_id
    JOIN ingredients i ON ir.ingredient_id = i.id
    WHERE i.name = 'Tomatoes'
)

我建议使用子查询而不是连接。有点像。。。

SELECT *
    FROM cuisine
    WHERE cuisine_id IN (
             SELECT cuisine_id
                 FROM recipe
                 WHERE recipe_id IN (
                         SELECT recipe_id
                             FROM recipe_ingredients
                             WHERE ingredient_id IN (
                                        SELECT id
                                        FROM ingredients
                                        WHERE TOUPPER(name) LIKE '%TOMATO%')));

无论如何,我认为你必须小心这个词的搭配;与其他记者相比更是如此,因为你不想错过“四个小番茄”或“一个大番茄”或“番茄泥”等配料。

存在变体:

SELECT name
FROM cuisines c
WHERE EXISTS
(   SELECT NULL 
    FROM recipes r 
    JOIN ingredients_recipes ir ON r.id = ir.recipe_id
    JOIN ingredients i ON ir.ingredient_id = i.id and i.name = 'tomatoes'
    WHERE r.cuisine_id = c.id
)