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Flask PyMongo-init\u app()缺少1个必需的位置参数:“app”

flask-pymongo flask-restful pymongo flask python

-1

Kay · 技术社区 · 6 年前

我正在尝试使用flask pymongo初始化我的数据库。

但我得到以下错误,

文件“run.py”,第22行,in
app=创建应用程序(“配置”)

TypeError:init\u app()缺少1个必需的位置参数:“app”

运行.py

from flask import Flask
from app import api_bp
from db import mongo

def create_app(config_filename):

    app = Flask(__name__)
    app.config.from_object(config_filename)
    app.register_blueprint(api_bp, url_prefix='/api')

    mongo.init_app(app)

    return app

# def logger():


# def database():


if __name__ == "__main__":
    app = create_app("config")
    app.run(host='0.0.0.0', port=8080, debug=True)

双倍

from flask_pymongo import PyMongo

mongo = PyMongo

DEBUG = True
SECRET_KEY = "secret"
MONGO_URI = "mongodb://localhost:27017/api"

应用程序/\uuu初始化\uuuuuuuuuuuuuuy.py

import os
import json
import datetime
from flask import Blueprint
from flask import jsonify
from flask_restful import Api
from .users.resource import UsersResource

api_bp = Blueprint('api', __name__)
api = Api(api_bp)


api.add_resource(UsersResource, '/users')

应用程序/用户/资源.py

from flask_restful import Resource
from flask import jsonify
from .repository import UsersRepository

class UsersResource(Resource):

    def __init__(self):

        self.repository = UsersRepository()

    def get(self):

        data = {"Users": "Resource"}
        res = data, 200
        return res

我正在尝试使用flaskrestful和flaskpymongo设置一个restfulapi。欢迎提出任何其他建议来改进我的方法。

2 回复 | 直到 6 年前

Daniel Roseman 6 年前

你没有在db.py中实例化PyMongo类。

mongo = PyMongo()

Feng 6 年前

你应该像我一样用烧瓶 this :

from flask import Flask
from flask_pymongo import PyMongo

app = Flask(__name__)
app.config["MONGO_URI"] = "mongodb://localhost:27017/myDatabase"
mongo = PyMongo(app)

因此,在run.py中,应该使用以下代码:

from flask import Flask
from app import api_bp
from db import mongo

def create_app(config_filename):

    app = Flask(__name__)
    app.config.from_object(config_filename)
    app.register_blueprint(api_bp, url_prefix='/api')

    # mongo.init_app(app) # remove this line

    return app

# def logger():


# def database():


if __name__ == "__main__":
    app = create_app("config")
    py_mongo = mongo(app)
    app.run(host='0.0.0.0', port=8080, debug=True)