两个时间间隔之间的差异查找问题

基本上,您需要做的是将这些时间值放入 DateTime 结构。一旦你有了你的两个 日期时间 变量,只需将它们相减-结果是一个类型的变量 TimeSpan :

DateTime dt1 = new DateTime(2010, 5, 7, 13, 45, 26, 836);
DateTime dt2 = new DateTime(2010, 5, 7, 14, 24, 18, 473);

TimeSpan result = dt2 - dt1;
string result2 = result.ToString();

TimeSpan有许多属性可以获取集合-各种单位的差异,例如毫秒、秒、分钟等。您还可以执行 .ToString() 获取结果的字符串表示形式。在 result2 你会得到这样的结果:

00:38:51.6370000

这就是你要找的吗?

我在张贴一个例子;

你可以检查它并调整你的程序,

/* Read the initial time. */
    DateTime startTime = DateTime.Now;
    Console.WriteLine(startTime);

    /* Do something that takes up some time. For example sleep for 1.7 seconds. */
    Thread.Sleep(1700);

    /* Read the end time. */
    DateTime stopTime = DateTime.Now;
    Console.WriteLine(stopTime);

    /* Compute the duration between the initial and the end time. 
     * Print out the number of elapsed hours, minutes, seconds and milliseconds. */
    TimeSpan duration = stopTime - startTime;
    Console.WriteLine("hours:" + duration.Hours);
    Console.WriteLine("minutes:" + duration.Minutes);
    Console.WriteLine("seconds:" + duration.Seconds);
    Console.WriteLine("milliseconds:" + duration.Milliseconds);

找出秒数,减去这两个数字,你就可以算出时间差。根据您使用的编程语言,我肯定他们一定是可以处理它的库。

//Start off with a string
string time1s = "13:45:26.836";
string time2s = "14:24:18.473";

TimeSpan interval = DateTime.Parse(time2s) - DateTime.Parse(time1s);

这将产生以下结果:

  Days    0   int         Hours   0   int
  Milliseconds    637 int
  Minutes 38  int         Seconds 51  int
  Ticks   23316370000 long
  TotalDays   0.02698653935185185 double
  TotalHours  0.64767694444444446 double
  TotalMilliseconds   2331637.0   double
  TotalMinutes    38.860616666666665  double
  TotalSeconds    2331.6369999999997  double