用python在三个重叠集合中查找delta

鉴于:

x = [1,2,3,4,5,6,7]
y = [2,1,4,5,8,10]
z = [7,1,3,6,0]

尝试:

x = set([1,2,3,4,5,6,7])
y = set([2,1,4,5,8,10])
z = set([7,1,3,6,0])

然后,您可以通过以下方式找到交点:

xy = x.intersection(y)
xyz = x.intersection(y).intersection(z)
# and
xyz = x & y & z

参见: https://docs.python.org/2/library/sets.html#set-objects

所有三角洲:

我用“x”代表“不在x”

x_y_z = z.difference(x).difference(y)
x_yz_ = y.difference(x).difference(z)
x_yz = y.intersection(z).difference(x)
xy_z_ = x.difference(y).difference(z)
xy_z = x.difference(y).intersection(z)
xyz_ = x.intersection(y).difference(z)
xyz = x.intersection(y).intersection(z)

根据@pascalvkooten的答案,我编写了代码来查找任意三个集合之间的所有delta。

所有三角洲:

我用“x”代表“不在x”

x_y_z = z.difference(x).difference(y)
x_yz_ = y.difference(x).difference(z)
x_yz = y.intersection(z).difference(x)
xy_z_ = x.difference(y).difference(z)
xy_z = x.difference(y).intersection(z)
xyz_ = x.intersection(y).difference(z)
xyz = x.intersection(y).intersection(z)

使用以下方法测试代码: 每个结果集的交集应为空集。

x_y_z.intersection(x_yz_).
intersection(x_yz).\
intersection(xy_z).\
intersection(xy_z_).\
intersection(xy_z).\
intersection(xyz_).\
intersection(xyz)

2. 结果集的并集应等于三个集的并集。

   x_y_z.联合(x_yz_u).联合(xy_z_u).联合(xy_z_u).\ 并集(x y z)==x.union(y.union(z)'