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对象键、切片和拼接

splice object arrays javascript

5

Eleven11 · 技术社区 · 7 年前

所以我还在学习数组和对象,我有点卡住了。我举了一个对象数组的例子:

var something = {candy:[{name:"snickers", price:2},
                    {name:"bounty", price:3},
                    {name:"mars", price:4}]};

Object.keys(something.candy).filter(function(obj){
return console.log(something.candy[obj].name);
})

1.问题-为什么我写作时它不起作用:

var candy1 = Object.keys(something.candy);
candy1.filter(function(obj){
return console.log(obj.name);
});

2.问题:为什么切片工作而拼接不工作???

Object.keys(something.candy).filter(function(obj){
return console.log(something.candy[obj].name.slice(0,3));
})

Object.keys(something.candy).filter(function(obj){
return a(something.candy[obj].name.splice(1,3));
})

1 回复 | 直到 7 年前

1

3

Mark 7 年前

在学习这一点的时候,把每一部分都分开来看是很有帮助的。例如,您有一个对象:

var something = {candy:[{name:"snickers", price:2},
                {name:"bounty", price:3},
                {name:"mars", price:4}]};

// what is something.candy:

console.log("candy:", something.candy)

// an array -- so what do you get with Object.keys?

var candy1 = Object.keys(something.candy)
console.log("keys:", candy1)

// just the indexes!

// So when you try to filter
candy1.filter(function(obj){
    // there is no obj.name becuase each object is just a number
    return console.log(obj);
});

我想你只需要这样做:

var something = {candy:[{name:"snickers", price:2},
                    {name:"bounty", price:3},
                    {name:"mars", price:4}]};

var select = something.candy.filter(obj => {
  console.log(obj.name) // look at them all
  return obj.name === "mars" // just pick this one
})

console.log("filtered: ", select)