scipy。pdist()返回NaN值

但是,当我运行Z=linkage(dist)时,以下代码返回错误,因为dist中有一些NaN值。在time_序列中没有NaN值,这由

np.any(isnan(time_series))

返回False

from scipy.spatial.distance import pdist
from scipy.cluster.hierarchy import dendrogram, linkage

dist = pdist(time_series, metric='correlation') 
Z = linkage(dist)
fig = plt.figure()
dn = dendrogram(Z)
plt.show()

作为替代,我将使用皮尔逊距离

from scipy.stats import pearsonr

def pearson_distance(a,b):
    return 1 - pearsonr(a,b)[0]

dist = pdist(time_series, pearson_distance)`