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Apollo Graphql:在重新蚀刻期间避免加载指示器

apollo-client react-apollo apollo graphql

3

Vimalraj Selvam MIZ · 技术社区 · 8 年前

import React, { Component } from 'react';
import { gql, graphql } from 'react-apollo';
import _ from 'underscore';

class Test extends Component {

    render() {
        if (this.props.TestData.loading) {
            return <div>Loading...</div>
        }

        if (this.props.TestData.error && this.props.TestData.error !== null) {
            return <div>Error...</div>
        }

        // Iterate through the this.props.TestData.getTestData and build the Table of data here
        return (
            <table>
                _.map(this.props.TestData.getTestData.testList, (test) => {
                    <tr>
                        <td>{test.testName}</td>
                        <td>{test.status}</td>
                    </tr>
                })
            </table>
        );
    }

}

const TestQuery = gql`
    query TestQuery() {
        getTestData() {
            testList {
                testName
                status
            }
        }
    }
`;

const options = () => ({
    pollInterval: 30000,
});

const withTestData = graphql(TestQuery, { 
    name: 'TestData',
    options, 
});

export default withTestData(Test);

Loading... 因为查询被重新触发。我想要 加载。。。 指示器指向用户。不确定如何实现这一点。

1 回复 | 直到 8 年前

1

3

Daniel Rearden 8 年前

data.loading ,但在大多数情况下,检查查询结果是否为null也同样有效:

// Should probably check this first. If you error out, usually your data will be
// undefined, which means putting this later would result in it never getting
// called. Also checking if it's not-null is a bit redundant :)
if (this.props.TestData.error) return <div>Error...</div>

// `testList` will only be undefined during the initial fetch
// or if the query errors out
if (!this.props.TestData.getTestData) return <div>Loading...</div>

// Render the component as normal
return <table>...</table>

还请记住,GraphQL可能返回一些错误,并且数据仍将返回。这意味着在生产环境中,您可能需要更健壮的错误处理行为,如果存在任何错误,则不一定会阻止页面呈现。