如何在Java中对哈希映射的值进行排序并保留重复的条目?

This 是一种可以使用的不同方法。比较器中的compare()方法在equal上不返回0。这将保留重复条目。

答案,我发现 here .

    public LinkedHashMap sortHashMapByValuesD(HashMap passedMap) {
    List mapKeys = new ArrayList(passedMap.keySet());
    List mapValues = new ArrayList(passedMap.values());
    Collections.sort(mapValues);
    Collections.sort(mapKeys);

    LinkedHashMap sortedMap = 
        new LinkedHashMap();

    Iterator valueIt = mapValues.iterator();
    while (valueIt.hasNext()) {
        Object val = valueIt.next();
        Iterator keyIt = mapKeys.iterator();

        while (keyIt.hasNext()) {
            Object key = keyIt.next();
            String comp1 = passedMap.get(key).toString();
            String comp2 = val.toString();

            if (comp1.equals(comp2)){
                passedMap.remove(key);
                mapKeys.remove(key);
                sortedMap.put((String)key, (Double)val);
                break;
            }
        }
    }

    return sortedMap;
}

public LinkedHashMap sortHashMapByValuesD(HashMap passedMap) {
List mapKeys = new ArrayList(passedMap.keySet());
List mapValues = new ArrayList(passedMap.values());
Collections.sort(mapValues);
Collections.sort(mapKeys);

LinkedHashMap sortedMap = 
    new LinkedHashMap();

Iterator valueIt = mapValues.iterator();
while (valueIt.hasNext()) {
    Object val = valueIt.next();
    Iterator keyIt = mapKeys.iterator();

    while (keyIt.hasNext()) {
        Object key = keyIt.next();
        String comp1 = passedMap.get(key).toString();
        String comp2 = val.toString();

        if (comp1.equals(comp2)){
            passedMap.remove(key);
            mapKeys.remove(key);
            sortedMap.put((String)key, (Double)val);
            break;
        }

    }

}
return sortedMap;

}