代码之家 › 专栏 › 技术社区 › Alex03

Oracle数据透视/解码

pivot-table oracle sql

Alex03 · 技术社区 · 6 年前

样本表

EmployeeID | AssignmentID | WageCode | CompanyName | BillRate | BillTotal    
     1     |       1      | Regular  | CompanyOne  |   10     |    400
     1     |       2      | Regular  | CompanyTwo  |   11     |    440
     1     |       1      | Overtime | CompanyOne  |   15     |    150
     1     |       1      | Mileage  | CompanyOne  |    0     |     20
     2     |       3      | Regular  | CompanyThree|   20     |    800
     2     |       3      | Regular  | CompanyThree|   20     |    800
     2     |       3      | Overtime | CompanyThree|   30     |     90
     2     |       3      | Mileage  | CompanyThree|    0     |     60

我只想显示按EmployeeID、WageCode、AssignmentID、CompanyName和BillRate分组的wageCode为“Regular”的行,并将其他工资代码透视到列中。

最终结果应如下所示:

EmployeeID | AssignmentID  | CompanyName | RegBillRate | RegBill | OTBillRate | OTBill | MileageBill
    1      |      1        | CompanyOne  |    10       |    400  | 15         |    150 |        20
    1      |      2        | CompanyTwo  |    11       |    440  |  0         |      0 |         0
    2      |      3        | CompanyThree|    20       |    1600 |  30        |     90 |        60

要做到这一点,有什么更清洁的方法?这不是一堆这样的陈述:

with regular as 
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Regular' group by EmployeeID, AssignmentID, CompanyName, BillRate
),
overtime as 
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Overtime' group by EmployeeID, AssignmentID, CompanyName, BillRate
),   
mileage as 
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Mileage' group by EmployeeID, AssignmentID, CompanyName, BillRate
)
select r.*, o.BillRate, o.Total, m.Total
from regular r 
left outer join overtime o
on r.EmployeeID = o.EmployeeID and r.AssignmentID= o.AssignmentID and r.CompanyName= o.CompanyName and r.BillRate= o.BillRateand 
left outer join mileage m
on r.EmployeeID = m.EmployeeID and r.AssignmentID= m.AssignmentID and r.CompanyName= m.CompanyName and r.BillRate= m.BillRateand

上面的查询是解释的,可能不起作用。

有什么更好的方法可以通过解码和透视的组合来实现这一点?是否可以使用单个透视表?

2 回复 | 直到 6 年前

Niharika Bitra 6 年前

枢轴: Oracle Pivot子句允许您从Oracle11g开始编写一个交叉表查询。这意味着您可以聚合结果并将行旋转为列。

译码: Oracle/PLSQL解码函数具有if-then-else语句的功能。

对于您的用例,可以使用pivot并按以下方式解码:

SELECT 
    EmployeeID, AssignmentID, CompanyName, 
    decode(REG_BILLRATE, NULL, 0, REG_BILLRATE) AS REG_BILLRATE,
    decode(REG_FILL, NULL, 0, REG_FILL) AS REG_FILL,
    decode(OT_BILLRATE, NULL, 0, OT_BILLRATE) AS OT_BILLRATE,
    decode(OT_FILL, NULL, 0, OT_FILL) AS OT_FILL,
    decode(MILEAGE_FILL, NULL, 0, MILEAGE_FILL) AS MILEAGE_FILL 
FROM nbitra.tmp
pivot
(
    max(BillRate) AS BillRate, sum(BillTotal) AS Fill
    for WageCode IN ('Regular' Reg , 'Overtime' OT , 'Mileage' Mileage )
);

注意:代码将空值替换为0。

Gordon Linoff 6 年前

我认为您只需要条件聚合:

select EmployeeID, AssignmentID, CompanyName,
       sum(case when WageCode = 'Regular' then billrate end) as regular_billrate,
       sum(case when WageCode = 'Regular' then BillTotal end) as regular_billtotal,
       sum(case when WageCode = 'Overtime' then billrate end) as ot_billrate,
       sum(case when WageCode = 'Overtime' then BillTotal end) as ot_billtotal,
       sum(case when WageCode = 'Mileage' then billrate end) as mileage_billrate,
       sum(case when WageCode = 'Mileage' then BillTotal end) as mileage_billtotal
from SampleTable st
group by EmployeeID, AssignmentID, CompanyName;