有人可能会提出不同的问题:如果单击其中任何一行,matplotlib如何知道要拖动哪一行?答:不会,因为它有三个回调,每行一个,并将全部执行。
因此,解决方案是首先检查单击的线是否实际上是要在
'pick_event'
回调:
if event.artist == self.line:
# register other callbacks
canvas.draw()
经常如此,但是
canvas.draw_idle()
)
import matplotlib.pyplot as plt
import matplotlib.lines as lines
class draggable_lines:
def __init__(self, ax, kind, XorY):
self.ax = ax
self.c = ax.get_figure().canvas
self.o = kind
self.XorY = XorY
if kind == "h":
x = [-1, 1]
y = [XorY, XorY]
elif kind == "v":
x = [XorY, XorY]
y = [-1, 1]
self.line = lines.Line2D(x, y, picker=5)
self.ax.add_line(self.line)
self.c.draw_idle()
self.sid = self.c.mpl_connect('pick_event', self.clickonline)
def clickonline(self, event):
if event.artist == self.line:
print("line selected ", event.artist)
self.follower = self.c.mpl_connect("motion_notify_event", self.followmouse)
self.releaser = self.c.mpl_connect("button_press_event", self.releaseonclick)
def followmouse(self, event):
if self.o == "h":
self.line.set_ydata([event.ydata, event.ydata])
else:
self.line.set_xdata([event.xdata, event.xdata])
self.c.draw_idle()
def releaseonclick(self, event):
if self.o == "h":
self.XorY = self.line.get_ydata()[0]
else:
self.XorY = self.line.get_xdata()[0]
print (self.XorY)
self.c.mpl_disconnect(self.releaser)
self.c.mpl_disconnect(self.follower)
fig = plt.figure()
ax = fig.add_subplot(111)
Vline = draggable_lines(ax, "h", 0.5)
Tline = draggable_lines(ax, "v", 0.5)
Tline2 = draggable_lines(ax, "v", 0.1)
plt.show()