是否有任何方法可以将void ptr“强制转换”到C中内联的结构指针?

请注意,以下代码是通过void指针访问结构的人为示例,否则没有意义 。我的问题是,是否有另一种方法(通过使用(cast*)样式的语法)将void指针转换为内联结构指针?E、 G.我可以避开电话线吗 S_TEST *tester_node_ptr = tester_node.next; 然后直接在printf调用中进行强制转换?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//Set up our data structure
typedef struct test{
    int field1;
    int field2;
    char name[50];
    void *next; // We will use this void * to refer to another struct test "node" for demo purposes
} S_TEST;



int main(void)
{
    S_TEST tester_node;
    S_TEST tester_node2;
    tester_node.field1 = 55;
    tester_node.field2 = 25;
    strcpy(tester_node.name, "First Node");
    tester_node.next = &tester_node2; // We put the addr of the second node into the void ptr
    tester_node2.field1 = 775;
    tester_node2.field2 = 678;
    strcpy(tester_node2.name, "Second Node");
    tester_node2.next = NULL; // End of list


    S_TEST *tester_node_ptr = tester_node.next;
    printf("The second node's name is: %s", tester_node_ptr->name);


    return EXIT_SUCCESS;
}