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Java:针对包含另一个xsd的xsd的字符串xml验证

include xsd validation java

Simon · 技术社区 · 7 年前

更新1:New Validation method抛出新错误,请参见下文。

希望有人知道我错在哪里。

我目前正在尝试根据包含另一个xsd的xsd验证xml文件。我不知道我的XSD或java代码是否有故障。我没有存储xml/xsd文件,而是将它们作为base64字符串从服务器获取。希望有人能帮忙。

org.xml.sax.SAXParseException; lineNumber: 81; columnNumber: 104; src-resolve: Cannot resolve the name 'ServiceSpecificationSchema:ServiceIdentifier' to a(n) 'type definition' component.

-ServiceSpecificationSchema。xsd

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ServiceSpecificationSchema="http://example.org/ServiceSpecificationSchema.xsd" targetNamespace="http://example.org/ServiceSpecificationSchema.xsd" version="1.0" xml:lang="EN">

    <include schemaLocation="ServiceBaseTypesSchema.xsd"/>
    <element name="serviceSpecification" type="ServiceSpecificationSchema:ServiceSpecification">
        <unique name="serviceDataModelTypeKey">
            <selector xpath=".//xs:*"/>
            <field xpath="@name"/>
        </unique>
        <keyref name="serviceDataModelReturnValueTypeKeyRef" refer="ServiceSpecificationSchema:serviceDataModelTypeKey">
            <selector xpath=".//ServiceSpecificationSchema:returnValueType"/>
            <field xpath="ServiceSpecificationSchema:typeReference"/>
        </keyref>
        <keyref name="serviceDataModelParameterTypeTypeKeyRef" refer="ServiceSpecificationSchema:serviceDataModelTypeKey">
            <selector xpath=".//ServiceSpecificationSchema:parameterType"/>
            <field xpath="ServiceSpecificationSchema:typeReference"/>
        </keyref>
    </element>
    <complexType name="ServiceSpecification">
        <all>
            <element name="id" type="ServiceSpecificationSchema:ServiceIdentifier" minOccurs="1" maxOccurs="1"/>
.....

ServiceBaseTypeSchema:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ServiceSpecificationSchema="http://example.org/ServiceSpecificationSchema.xsd" targetNamespace="http://example/ServiceSpecificationSchema.xsd" version="1.0" xml:lang="EN">
...
    <simpleType name="ServiceIdentifier">
        <restriction base="string"/>
    </simpleType>
...
</schema>

Java验证器

public void validate(String inputXml, String XSD, String XSD2)
        throws SAXException, IOException {
        try {
            byte[] decoded = Base64.decodeBase64(XSD);
            XSD = new String(decoded, "UTF-8");
            byte[] decoded2 = Base64.decodeBase64(XSD2);
            XSD2 = new String(decoded2, "UTF-8");

        SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

        Schema schema = factory.newSchema(new SAXSource[]
        {
        (new SAXSource(new InputSource(new StringReader(XSD)))),
        (new SAXSource(new InputSource(new StringReader(XSD2))))
        });

        Validator validator = schema.newValidator();
        validator.validate(new StreamSource(new StringReader(inputXml)));
        } catch (SAXException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
        } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
        }

}

我找到了另一个可能的解决方案,但仍然不起作用。使用以下方法,抛出exeption,根据xml验证XSD。例外行取决于使用的xml。在底部的示例中,错误在第2行-&燃气轮机;错误: 找不到元素“ServiceSpecificationSchema:serviceSpecification”的声明

新Java验证器:

byte[] decoded = Base64.decodeBase64(XSD);
                byte[] decoded2 = Base64.decodeBase64(XSD2);

                SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

                InputStream impFis = new ByteArrayInputStream(decoded2);
                InputStream mainFis = new ByteArrayInputStream(decoded);

                Source main = new StreamSource(mainFis);
                Source imp = new StreamSource(impFis);
                Source[] schemaFiles = new Source[] {imp, main};
                Schema schema = factory.newSchema(schemaFiles);
                Validator validator = schema.newValidator();
                validator.validate(new StreamSource(new StringReader(inputXml)));

XML文件示例:

<?xml version="1.0" encoding="UTF-8"?>
<ServiceSpecificationSchema:serviceSpecification
        xmlns:ServiceSpecificationSchema="http://example.org/ServiceSpecificationSchema.xsd"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://example.org/ServiceSpecificationSchema.xsd">
.....

1 回复 | 直到 7 年前

Simon 7 年前

这对我来说很有用:

@Service
public class ResourceResolverImpl implements LSResourceResolver {
private ILoadFromSRService iLoadFromSRService;

@Autowired
public ResourceResolverImpl(ILoadFromSRService iLoadFromSRService){
    this.iLoadFromSRService = iLoadFromSRService;
}

public LSInput resolveResource(String type,
                               String namespaceURI,
                               String publicId,
                               String systemId,
                               String baseURI) {
    String string =iLoadFromSRService.getServiceBaseTypeSchema();
    string = string.replace("\n", "").replace("\t", "");
    InputStream resourceAsStream = new ByteArrayInputStream( string.getBytes());
    return new LSInputImpl(publicId, systemId, resourceAsStream);
    }
}