任务如何在多个vxworks队列上等待?

每当触发select()时,您都会处理高优先级管道中的所有消息。然后处理来自低优先级管道的单个消息。然后再次调用select(循环)。

示例代码段:

 // Initialization: Create high and low priority named pipes
 pipeDrv(); //initialize pipe driver
 int fdHi = pipeDevCreate("/pipe/high",numMsgs,msgSize);
 int fdLo = pipeDevCreate("/pipe/low",numMsgs,msgSize);

 ...

 // Message sending thread: Add messages to pipe
 write(fdHi, buf, sizeof(buf));

 ...

 // Message processing Thread: select loop
 fd_set rdFdSet;

 while(1)
 {
     FD_ZERO(&rdFdSet);
     FD_SET(fdHi, &rdFdSet);
     FD_SET(fdLo, &rdFdSet;

     if (select(FD_SETSIZE, &rdFdSet, NULL, NULL, NULL) != ERROR)
     {
         if (FD_ISSET(fdHi, &rdFdSet))
         {
             // process all high-priority messages
             while(read(fdHi,buf,size) > 0)
             {
                 //process high-priority
             }
         }

         if (FD_ISSET(fdLo, &rdFdSet))
         {
             // process a single low priority message
             if (read(fdLo,buf,size) > 0)
             {
                 // process low priority
             }
         }
     }
 }

在vxWorks中,您不能直接在多个队列上等待。但是,您可以使用OS事件(来自eventLib)来实现此结果。 下面是一个简单的代码片段:

MSG_Q_ID lowQ, hiQ;

void Init() {
// Task Initialization Code.  This should be called from the task that will
// be receiving the messages
...
hiQ = msgQCreate(...);
lowQ = msgQCreate(...);
msgQEvStart(hiQ, VX_EV01);  // Event 1 sent when hiQ receives message
msgQEvStart(loQ, VX_EV02);  // Event 2 sent when loQ receives message
...
}
void RxMessages() {
...
  UINT32 ev;   // Event received

   // Blocks until we receive Event 1 or 2
   eventReceive(VX_EV01 | VX_EV02, EVENT_WAIT_ANY, WAIT_FOREVER, &ev);
   if(ev & VX_EV01) {
      msgQReceive(hiQ, ...);
   }
   if(ev & VX_EV02) {
      msgQReceive(loQ, ...);
   }
}

请注意,您需要修改该代码,以确保在收到多条消息的情况下耗尽所有队列。

同样的机制也可以使用semEvStart()函数应用于二进制信号量。