创建iOS客户端服务器应用程序。ASIFormDataRequest问题

我的问题是: 如何使用创建与以下相同的请求 ASIFormDataRequest 其次,我认为我需要从响应中解析JSON。

http://exampledomain.com/mobile_api/register/?client=iphone&info=A=iPhone/OS=5.1/C=UA&time=1342780143&udid=8b6f0cc104d137ae2e1730235f5664094b831122&version=1.0&secure=5444d72741bad93b916577d9297fa

现在我尝试使用这样的代码

NSString *strURL = @"http://test2.mafia.ua/mobile_api/register/";
    ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:strURL]];
    [request setDelegate:self];
    [request setPostValue:@"iphone" forKey:@"client"];
    [request setPostValue:@"A=iPhone/OS=5.1/C=UA" forKey:@"info"];
    [request setPostValue:@"1342780143" forKey:@"time"];
    [request setPostValue:@"8b6f0cc104d137ae2e1730235f5664094b831122" forKey:@"udid"];
    [request setPostValue:@"1.0" forKey:@"version"];
    [request setPostValue:@"5444d72741bad93b916577d9297fa" forKey:@"secure"];
    [request startAsynchronous];

这是正确的吗?

我也执行委托方法

- (void)requestFinished:(ASIHTTPRequest *)request {

    NSLog(@"Response %d ==> %@", request.responseStatusCode, [request responseString]);

}
- (void)requestFailed:(ASIHTTPRequest *)request {

}

作为回应,如果我使用一些浏览器,我会得到这个(我认为这是JSON)。

{“status”:“ok”,“secret”:“b82b7771f600772c2c5af903b117b5e”,“client”:“200004”,“expires”:“1345372850”}