类似“Date:01Jan2022”的字符串的正则表达式

假设缩写月份总是三个字母,您可以简单地使用:

inp = ["01JAN2022", "blah"]
for i in inp:
    if re.search(r'^\d{2}[A-Z]{3}\d{4}$', i):
        print("Found a date: " + i)
    else:
        print("Not a date:   " + i)

更准确地说,我们可以使用包含所有12个缩写月份的替代:

inp = ["01JAN2022", "blah"]
regex = r'^\d{2}(?:JAN|FEB|MAR|APR|MAY|JUN|JUL|AUG|SEP|OCT|NOV|DEC)\d{4}$'
for i in inp:
    if re.search(regex, i):
        print("Found a date: " + i)
    else:
        print("Not a date:   " + i)