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如何在workmanagerforandroid中创建带有参数的Worker?

android-workmanager android-architecture-components kotlin android

Joshua · 技术社区 · 6 年前

Android架构有一个新的组件 WorkManager .

class CompressWorker(context : Context, params : WorkerParameters)
    : Worker(context, params) {

    override fun doWork(): Result {

        // Do the work here--in this case, compress the stored images.
        // In this example no parameters are passed; the task is
        // assumed to be "compress the whole library."
        myCompress()

        // Indicate success or failure with your return value:
        return Result.SUCCESS

        // (Returning RETRY tells WorkManager to try this task again
        // later; FAILURE says not to try again.)

    }

}

val compressionWork = OneTimeWorkRequestBuilder<CompressWorker>().build()

Worker 接受构造函数或 doWork ?

1 回复 | 直到 6 年前

Dhaval Patel 6 年前

你可以用 setInputData

/***  Logic to set Data while creating worker **/
val compressionWork = OneTimeWorkRequest.Builder(CompressWorker::class.java)
val data = Data.Builder()
//Add parameter in Data class. just like bundle. You can also add Boolean and Number in parameter.
data.putString("file_path", "put_file_path_here")
//Set Input Data
compressionWork.setInputData(data.build())
//enque worker
WorkManager.getInstance().enqueue(compressionWork.build())


/*** Logic to get Data  ***/
class CompressWorker(context : Context, params : WorkerParameters)
    : Worker(context, params) {

    override fun doWork(): Result {

        //get Input Data back using "inputData" variable 
        val filePath =  inputData.getString("file_path")

        // Do the work here--in this case, compress the stored images.
        // In this example no parameters are passed; the task is
        // assumed to be "compress the whole library."
        myCompress()

        // Indicate success or failure with your return value:
        return Result.SUCCESS

        // (Returning RETRY tells WorkManager to try this task again
        // later; FAILURE says not to try again.)

    }

}

有关更多信息,请访问 link .

Pratik Butani Umesh N 5 年前

在Java中:

    Constraints.Builder builder = new Constraints.Builder()
            .setRequiredNetworkType(NetworkType.CONNECTED);

    // Passing params
    Data.Builder data = new Data.Builder();
    data.putString("SyncMaster", syncModuleName);

    OneTimeWorkRequest syncWorkRequest =
            new OneTimeWorkRequest.Builder(SyncWorker.class)
                    .addTag("Sync")
                    .setInputData(data.build())
                    .setConstraints(builder.build())
                    .build();

    WorkManager.getInstance().enqueue(syncWorkRequest);

你可以这样:

public class SyncWorker extends Worker {

    private static final String TAG = "MyWorker";

    public SyncWorker(@NonNull Context context, @NonNull WorkerParameters workerParams) {
        super(context, workerParams);
        mContext = context;
    }

    @NonNull
    @Override
    public Result doWork() {
        Log.d(TAG, "doWork for Sync");
        String syncTable = getInputData().getString("SyncMaster");
        return Result.success();
    }
}

希望它能帮上忙。

-1

Vaibhav Pallod 4 年前

当我使用WorkManager并试图向它传递一些对象时

Data data = new Data.Builder().put("passstring",object).build();

getting me Builder.put只能从同一个库组(groupId=androidx.work)中调用错误你有解决办法吗?