当我将光标移到元素上而不离开元素时调用onmouseout JavaScript事件

onmouseover 我将调用一个JavaScript函数来显示工具提示,并在 onmouseout

如果我在图像中移动鼠标,它会调用 事件(即使我没有脱离图像)。我怎样才能阻止这一切?我想要 当光标离开图像时调用。有什么想法吗?

我这样称呼它:

 <img src="images/customer.png" onmouseout="HideCustomerInfo()" onmouseover="ShowCustomerInfo(485)" />

在我的JavaScript中:

 function ShowCustomerInfo(id) {


 var currentCustomer = $("#hdnCustomerId").val();   
 if (currentCustomer != id) { // to stop making an ajax call everytime when the mouse move on the same image
     
     $.get('../Lib/handlers/userhandler.aspx?mode=custinfo&cid=' + id, function (data) {
         strHtml = data;
     });

     tooltip.show(strHtml);   // method in another jquery pluggin
     $("#hdnCustomerId").val(id);
 }
}

function HideCustomerInfo() {

 tooltip.hide();    // method in another jquery pluggin
 $("#hdnCustomerId").val(0); //setting in a hidden variable in the page

 }