情况如下:
RestTemplate
在你的服务课上。
private RestTemplate restTemplate = new RestTemplate();
然后创建模拟测试并调用服务方法:
RestTemplate restTemplate = Mock {
postForEntity(_, _, SomeResponse.class) >> new ResponseEntity(new SomeResponse(), HttpStatus.OK)
}
....
someService.doSomePostRequest
但您的服务中仍然包含常见的rest模板。您应该注入模拟对象。我建议你通过构造函数来做。因此,请将代码更改为:
@Service
public class SomeService {
private EndpointUrlProvider endpointUrlProvider;
private RestTemplate restTemplate;
@Autowired
public SomeService(EndpointUrlProvider endpointUrlProvider, RestTemplate restTemplate){
this.endpointUrlProvider = endpointUrlProvider;
this.restTemplate = restTemplate;
}
您的测试将是:
class SomeTest extends Specification {
RestTemplate restTemplate = Mock {
postForEntity(_, _, SomeResponse.class) >> new ResponseEntity(new SomeResponse(), HttpStatus.OK)
}
SomeService someService = new SomeService ( null, restTemplate);
def "someTest"() {
when:
SomeResponse someResponse = someService.doSomePostRequest(new HttpEntity<>(new SomeBody(), new HttpHeaders()))
then:
someResponse == new SomeResponse()
}
}
现在,您的服务对象将在注入的MOCK上调用方法,这并不常见
RestTemplate
附笔
spring认为构造函数注入是一种很好的做法。
与在所有服务中创建新对象相比,最好创建RestTemplate bean并将其注入到任何地方。