gcc内联程序集作为二进制数组

你可以定义一个函数,编译它,然后得到它的源代码?

#include <stdio.h>
#include <stdint.h>
#include <stddef.h>

void my_func(void) {}

extern void my_code(void);
extern void my_code_end(void);

__attribute__((__used__)) static void _my_code(void) {
        asm volatile(
                ".globl my_code\n"
                "my_code:\n"
                "  callq *%0\n"
                "  nop\n"
                "  ret\n"
                ".globl my_code_end\n"
                "my_code_end:\n"
                :: "r" (my_func)
        );
}

int main() {
        size_t my_code_len = (uintptr_t)my_code_end - (uintptr_t)my_code;
        const unsigned char *arr = (const char*)my_code;
        printf("my_code[%zu]=", my_code_len);
        for (size_t i = 0; i < my_code_len; ++i) {
                printf("%02x", arr[i]);
        }
        printf("\n");
        return 0;
}

示例输出:

my_code[4]=ffd090c3

我们可以从程序集输出中检查它是否正常:

$ objdump -D ./a.out
...
0000000000000727 <my_code>:
 727:   ff d0                   callq  *%rax
 729:   90                      nop
 72a:   c3                      retq   
...