在新行中设置包含多个值的变量

你需要插入 <LF> 变量定义中的字符 使用延迟扩展显示其值:

@echo off
setlocal EnableDelayedExpansion

set "var1=One"
set "var2=Two"
set "var3=Three"
set "var4=Four"

set ^"EmailText=%var1%^

%var2%^

%var3%^

%var4%^"

echo !EmailText!

尽管可以删除定义中变量值之间的空行,但所需的语法既难看又尴尬。。。

编辑 :新版本以实现 新的 评论中的要求。。。

@echo off
setlocal EnableDelayedExpansion

for /F %%a in ('copy /Z "%~F0" NUL') do set "CR=%%a"

set "var1=One"
set "var2=Two"
REM set "var3=Three"
set "var4=Four"

set "EmailText="
for %%v in (var1 var2 var3 var4) do (
   if defined %%v set ^"EmailText=!EmailText!!%%v!!CR!^
%Do not remove this line%
^"
)

echo !EmailText!

One
Two
Four

下面的脚本测试每个变量是否有内容,并将字符串附加在一起。如果文本中可以出现分号,请选择另一个字符作为换行分隔符。

@echo off
setlocal EnableDelayedExpansion

set "var1=One"
set "var2=Two"
set "var3=Three"
set "var4=Four"

SET LF=^


REM Do not remove blank lines for LF.

set "EmailText="
IF NOT "%var1%" == "" (SET "EmailText=%EmailText%%var1%;")
IF NOT "%var2%" == "" (SET "EmailText=%EmailText%%var2%;")
IF NOT "%var3%" == "" (SET "EmailText=%EmailText%%var3%;")
IF NOT "%var4%" == "" (SET "EmailText=%EmailText%%var4%")

SET "EmailText=%EmailText:;=!LF!%"

echo !EmailText!
EXIT /B 0

示例运行:

12:56:51.62  C:\src\t\emailtext
C:>emailtext.bat >t.txt

12:57:07.74  C:\src\t\emailtext
C:>type t.txt
One
Two
Three
Four