从Bash变量中剥离字符(2)

我有一个小脚本,我需要从第一个句点('.')中去掉所有内容。

我用 ${i%.*}

#!/bin/bash
today=$(date +"%Y%m%d")
limdir="/some/dir/"

cd $limdir  || exit
  for i in *Limit*${today}.csv
      do
      echo $i 
      echo /var/tmp/casper/${i%.*}
      done

从上一个时期开始就失去了一切。

casper1LimitChanges.20180813.csv
/var/tmp/bin/script/xenon/casper1LimitChanges.20180813

casper1LimitSnapshot.20180813.csv
/var/tmp/bin/script/xenon/casper1LimitSnapshot.20180813

我要第一节课的所有东西。文件需要如下所示:

casper1LimitChanges.20180813.csv
/var/tmp/bin/script/xenon/casper1LimitChanges

casper1LimitSnapshot.20180813.csv
/var/tmp/bin/script/xenon/casper1LimitSnapshot