在PHP中使用单个数组时,我希望像like一样合并,并且能够这样做,但是在应该有2的地方,我只得到1返回值。
下面是原始数组和新数组。
id LIKE 'fghij' OR id LIKE 'abcde'
$orig = Array
(
[0] => Array
(
[id] => abcde
[field2] => height
[value2] => 40 ft.
)
[1] => Array
(
[id] => abcde
[field3] => width
[value3] => 10-15 ft.
)
[2] => Array
(
[id] => abcde
[field4] => light
[value4] => Full - Partial
)
[3] => Array
(
[id] => abcde
[field6] => space
[value6] => 5-6 ft.
)
[4] => Array
(
[id] => fghij
[field2] => height
[value2] => 4-8 ft.
)
[5] => Array
(
[id] => fghij
[field3] => width
[value3] => 3-4 ft.
)
[6] => Array
(
[id] => fghij
[field4] => light
[value4] => Full - Partial
)
[7] => Array
(
[id] => fghij
[field5] => season
[value5] => Spring
)
[8] => Array
(
[id] => fghij
[field6] => space
[value6] => 4 ft.
)
[9] => Array
(
[id] => fghij
[field19] => restricted
[value19] => CA, TX, LA, FL, AZ
)
[10] => Array
(
[id] => abcde
[field19] => restricted
[value19] => AZ
)
)
$new = Array
(
[id] => abcde
[field2] => height
[value2] => 4-8 ft.
[field3] => width
[value3] => 3-4 ft.
[field4] => light
[value4] => Full - Partial
[field6] => space
[value6] => 4 ft.
[field5] => season
[value5] => Spring
[field19] => restricted
[value19] => AZ
)
$new
是如此接近正确,但它忽略了与
fghij
,返回单个扁平数组。我希望它返回两个ID及其合并值。
这就是我在代码方面的工作:
$new_new = [];
foreach($orig as $key => $value){
if(is_array($value)){
$new_new = array_merge($new_new, $value);
}
}