获取函数参数的地址合法吗?

#include <stdio.h>

void foo(int a)
{
   printf("%p\n", &a);
}

int main(void)
{
   foo(42);
   return 0;
}

EDIT:看起来GCC会先将寄存器传递的值放入堆栈,然后再获取它的地址。

<foo>:
  55                      push   rbp
  48 89 e5                mov    rbp,rsp
  48 83 ec 10             sub    rsp,0x10
  89 7d fc                mov    DWORD PTR [rbp-0x4],edi
  b8 1c 06 40 00          mov    eax,0x40061c
  48 8d 55 fc             lea    rdx,[rbp-0x4]
  48 89 d6                mov    rsi,rdx
  48 89 c7                mov    rdi,rax
  b8 00 00 00 00          mov    eax,0x0
  e8 d8 fe ff ff          call   4003c0 <printf@plt>
  c9                      leave  
  c3                      ret