如何从我无法直接访问的线程捕获异常?

Start 方法运行 开始

执行顺序如下所示。箭头指示在不同线程中运行的内容:

-> MyService.Start -> pA.Start -> pb.Start -> return
                          \_> DoWork()  \
                                         \_> DoWork()

既然都 DoWork()

有什么建议可以避免这个问题吗?提前谢谢。

以下代码是对实际代码的过度简化:

public class MyService
{
    private PluginA pA = new PluginA();
    private PluginB pB = new PluginB();

    // Windows Service runs Start when the service starts. It must return ASAP
    public void Start()
    {
        // try..catch doesn't capture PluginB's exception
        pA.Start();
        pB.Start();
    }

    // Windows Service runs Stop when the service Stops. It must return ASAP
    public void Stop()
    {
        pA.Stop();
        pB.Stop();
    }
}

// I have no control over how this is developed
public class PluginA
{
    private Timer _timer;

    public void Start()
    {
        _timer = new Timer(
            (e) => DoWork(),
            null,
            TimeSpan.Zero,
            TimeSpan.FromSeconds(10));
    }

    private void DoWork()
    {
        File.AppendAllText(
            "C:/log.txt",
            "hello" + Environment.NewLine);
    }

    public void Stop()
    {
        _timer.Change(Timeout.Infinite, 0);
    }
}

// I have no control over how this is developed
public class PluginB
{
    private Timer _timer;

    public void Start()
    {
        _timer = new Timer(
            (e) => DoWork(),
            null,
            TimeSpan.Zero,
            TimeSpan.FromSeconds(10));
    }

    private void DoWork()
    {
        File.AppendAllText(
            "C:/log.txt",
            "Goodbye" + Environment.NewLine);

        throw  new Exception("Goodbye");
    }

    public void Stop()
    {
        _timer.Change(Timeout.Infinite, 0);
    }
}