将元组列表转换为该列表中使用的所有整数的列表

如果您想使用替换方法,确实有一种简单的方法:

import re
factor_pairs = [(100, 1), (50, 2), (25, 4), (20, 5), (10, 10)]
s = re.sub(r'[\[\]\(\), ]', '', str(factor_pairs))
factor_numbers = [int(i) for i in set(s)]

外部字符中指定的任何字符 [] 的将被替换。

如果顺序不一定重要,则可以使用集合:

from itertools import chain

lst = [(100, 1), (50, 2), (25, 4), (20, 5), (10, 10)]

flst = map(lambda x: str(x), chain.from_iterable(lst))

s = set()
for x in flst:
    for i in x:
        s.add(i)

print(s)
# {'2', '1', '0', '5', '4'}

如果顺序很重要,请使用列表:

from itertools import chain

lst = [(100, 1), (50, 2), (25, 4), (20, 5), (10, 10)]

flst = map(lambda x: str(x), chain.from_iterable(lst))

s = []
for x in flst:
    for i in x:
        if i not in s:
            s.append(i)

print(s)
# ['1', '0', '5', '2', '4']