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与截图和文本一起共享URL

xcode7-beta5 share swift xcode

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Ben Bar · 技术社区 · 9 年前

我有一个很快的初学者问题:如何让这个函数也共享一个URL?我总是遵循每件事,并认为我做得对,但似乎不太奏效……提前感谢!

func takeSnapshot(view: UIView) {
    let bounds = UIScreen.mainScreen().bounds
    UIGraphicsBeginImageContextWithOptions(bounds.size, true, 0.0)
    self.view.drawViewHierarchyInRect(bounds, afterScreenUpdates: false)
    let image = UIGraphicsGetImageFromCurrentImageContext()
    UIGraphicsEndImageContext()
    let text = "Text to be shared... #Hashtag"
    let activityViewController = UIActivityViewController(activityItems: [image, text], applicationActivities: nil)
    self.presentViewController(activityViewController, animated: true, completion: nil)

1 回复 | 直到 9 年前

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Bannings 9 年前

只需添加一个 NSURL :

let bounds = UIScreen.mainScreen().bounds
UIGraphicsBeginImageContextWithOptions(bounds.size, true, 0.0)
self.view.drawViewHierarchyInRect(bounds, afterScreenUpdates: false)
let image = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
let text = "Text to be shared... #Hashtag"
let URL = NSURL(string: "http://stackoverflow.com/")!

let activityViewController = UIActivityViewController(activityItems: [image, text, URL], applicationActivities: nil)
self.presentViewController(activityViewController, animated: true, completion: nil)