我需要计算使用rijndael加密的文件的大小。
根据本网站和谷歌的其他答案,以下是计算加密数据长度的正确方法:
EL = UL + (BS - (UL Mod BS) Mod BS)
Where:
EL = Encrypted Length
UL = Unencrypted Length
BS = Block Size
在我的例子中,
未加密的文件长度为5101972字节
,我正在使用一个128位的加密密钥,给我一个
块大小为16字节
.
因此,方程为:
EL = 5101972 + (16 - (5101972 Mod 16) Mod 16)
EL = 5101972 + (16 - 4 Mod 16)
EL = 5101972 + (12 Mod 16)
EL = 5101972 + 12
EL = 5101984
给予一个
加密文件长度为5101984字节
.
但是,加密后我的文件大小为5242896
140912字节大小的巨大差异!
现在。。显然我做错了什么,但我搞不清是什么。
下面是我的加密和解密测试代码,以及用于计算加密大小的方法:
private static void Enc(string decryptedFileName, string encryptedFileName)
{
PasswordDeriveBytes passwordDB = new PasswordDeriveBytes("ThisIsMyPassword", Encoding.ASCII.GetBytes("thisIsMysalt!"), "MD5", 2);
byte[] passwordBytes = passwordDB.GetBytes(128 / 8);
using (FileStream fsOutput = File.OpenWrite(encryptedFileName))
{
using(FileStream fsInput = File.OpenRead(decryptedFileName))
{
byte[] IVBytes = Encoding.ASCII.GetBytes("1234567890123456");
fsOutput.Write(BitConverter.GetBytes(fsInput.Length), 0, 8);
fsOutput.Write(IVBytes, 0, 16);
RijndaelManaged symmetricKey = new RijndaelManaged() { Mode = CipherMode.CBC,Padding=PaddingMode.Zeros};
ICryptoTransform encryptor = symmetricKey.CreateEncryptor(passwordBytes, IVBytes);
using (CryptoStream cryptoStream = new CryptoStream(fsOutput, encryptor, CryptoStreamMode.Write))
{
for (long i = 0; i < fsInput.Length; i += chunkSize)
{
byte[] chunkData = new byte[chunkSize];
int bytesRead = 0;
while ((bytesRead = fsInput.Read(chunkData, 0, chunkSize)) > 0)
{
cryptoStream.Write(chunkData, 0, chunkSize);
}
}
}
}
}
}
private static void Dec(string encryptedFileName, string decryptedFileName)
{
PasswordDeriveBytes passwordDB = new PasswordDeriveBytes("ThisIsMyPassword", Encoding.ASCII.GetBytes("thisIsMysalt!"), "MD5", 2);
byte[] passwordBytes = passwordDB.GetBytes(128 / 8);
using (FileStream fsInput = File.OpenRead(encryptedFileName))
{
using (FileStream fsOutput = File.OpenWrite(decryptedFileName))
{
byte[] buffer = new byte[8];
fsInput.Read(buffer, 0, 8);
long fileLength = BitConverter.ToInt64(buffer, 0);
byte[] IVBytes = new byte[16];
fsInput.Read(IVBytes, 0, 16);
RijndaelManaged symmetricKey = new RijndaelManaged() { Mode = CipherMode.CBC,Padding=PaddingMode.Zeros};
ICryptoTransform decryptor = symmetricKey.CreateDecryptor(passwordBytes, IVBytes);
using (CryptoStream cryptoStream = new CryptoStream(fsOutput, decryptor, CryptoStreamMode.Write))
{
for (long i = 0; i < fsInput.Length; i += chunkSize)
{
byte[] chunkData = new byte[chunkSize];
int bytesRead = 0;
while ((bytesRead = fsInput.Read(chunkData, 0, chunkSize)) > 0)
{
cryptoStream.Write(chunkData, 0, bytesRead);
}
}
fsOutput.SetLength(fileLength);
}
}
}
}
private static void CalcEncSize(string decryptedFileName)
{
FileInfo fi = new FileInfo(decryptedFileName);
if (fi.Exists)
{
long blockSize = 128/8;
long fileLength = fi.Length;
long encryptedSize = fileLength + ((blockSize - (fileLength % blockSize)) % blockSize);
encryptedSize += 24; //16 bytes for the IV, and 8 more for the filelength, both stored at the start of the file.
Console.WriteLine("Estimated Encryption Size: " + encryptedSize.ToString());
}
}
注:在开始的计算中,我不包括在加密文件开始时自己用来存储原始文件长度的额外24个字节,以及IV…我知道这一点,但不想把方程复杂化。