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如何将Spring Security RemoteTokenService与KeyClope结合使用

keycloak spring-security java

HaVonTe · 技术社区 · 7 年前

我设置了一个keyclope服务器。配置了领域和客户端等。我成功地用“org.keydepeat:keydepeat-springbootstarter”编写了一个Spring引导服务,并保护了我的RestController。工作起来很有魅力。

但是,当我尝试使用Spring安全性(没有KeyClope特定的依赖项)时,我被卡住了。

这是我的gradle:

dependencies {
compile('org.springframework.boot:spring-boot-starter-security')
compile('org.springframework.security.oauth:spring-security-oauth2')

compile('org.springframework.boot:spring-boot-starter-web')
compileOnly('org.projectlombok:lombok')
testCompile('org.springframework.boot:spring-boot-starter-test')
testCompile('org.springframework.security:spring-security-test')

}

这是我的安全配置:

@Configuration
@EnableResourceServer
public class ResourceServerConfiguration extends 
ResourceServerConfigurerAdapter {

@Override
public void configure(HttpSecurity http) throws Exception {
    http.authorizeRequests()
        .antMatchers("/person/**").hasRole("DEMO_SPRING_SECURITY")
        .anyRequest().authenticated()
        .and().formLogin().disable();
}

@Override
public void configure(ResourceServerSecurityConfigurer resources) throws Exception {

    resources.resourceId("demo-client");
    RemoteTokenServices tokenServices = new RemoteTokenServices();
    tokenServices.setCheckTokenEndpointUrl(
        "http://localhost:8280/auth/realms/demo-realm/protocol/openid-connect/token/introspect");
    tokenServices.setClientId("demo-client");
    tokenServices.setClientSecret("80e19056-7770-4a4a-a3c4-06d8ac8792ef");
    resources.tokenServices(tokenServices);
}
}

现在我尝试访问服务器:

获取访问令牌(通过REST客户端) 解码后的JWT如下所示:

{
"jti": "78c00562-d80a-4f5a-ab08-61ed10cb575c",
"exp": 1509603570,
"nbf": 0,
"iat": 1509603270,
"iss": "http://localhost:8280/auth/realms/demo-realm",
"aud": "demo-client",
"sub": "6ee90ba4-2854-49c1-9776-9aa95b6ae598",
"typ": "Bearer",
"azp": "demo-client",
"auth_time": 0,
"session_state": "68ce12fb-3b3f-429d-9390-0662f0503bbb",
"acr": "1",
"client_session": "ec0113e1-022a-482a-a26b-e5701e5edec1",
"allowed-origins": [],
"realm_access": {
  "roles": [
    "demo_user_role",
    "uma_authorization"
  ]
},
"resource_access": {
  "account": {
    "roles": [
      "manage-account",
      "manage-account-links",
      "view-profile"
    ]
  }
},
"name": "Jim Panse",
"preferred_username": "demo-user",
"given_name": "Jim",
"family_name": "Panse",
"email": "user@dmoain.com"
}

但我得到了一个AccessDeniedException。

2017-11-02 07:18:05.344 DEBUG 17637 --- [nio-8080-exec-1] o.s.s.w.a.i.FilterSecurityInterceptor    : Previously Authenticated:
负责人:演示客户;凭据:[受保护];已验证:true; 详细信息:remoteAddress=127.0.0.1,tokenType=BeareTokenValue=; 未授予任何权限2017-11-02 07:18:05.348调试17637--- [nio-8080-exec-1]o.s.s.access。选票基于肯定的:选民: 组织。springframework。安全网状物通道表示WebExpressionVoter@14032696, 返回:-1 2017-11-02 07:18:05.353调试17637---[nio-8080-exec-1] 非匿名);授权给AccessDeniedHandler

组织。springframework。安全通道AccessDeniedException:访问是否认

我调试了RemoteTokenService,发现KeyClope使用完全相同的accesstoken进行响应。这很好。但是比 DefaultAccessTokenConverter 尝试从字段中读取用户角色 authorities 这是不存在的。和 OAuth2WebSecurityExpressionHandler 评估用户不具有任何角色--&燃气轮机;拒绝访问

所以我的问题是:

2 回复 | 直到 5 年前

Boomer 7 年前

通过KeyClope管理控制台,您可以创建类型为的令牌映射器 用户领域角色 您的客户“演示客户”的索赔名称为“授权”。然后,访问令牌包含此属性中的角色名称,并且没有自定义标记 DefaultAccessTokenConverter 是必需的。

HaVonTe 7 年前

在这里阐述了这个问题之后,我自己找到了一个解决方案。有时,试图表达一个问题会有所帮助。

解决方案是重写DefaultAccessTokenConverter,教他如何读取“realm\u access”字段。它很难看,但很管用:

@Override
public void configure(ResourceServerSecurityConfigurer resources) throws Exception {

    resources.resourceId("demo-client");
    RemoteTokenServices tokenServices = new RemoteTokenServices();
    tokenServices.setCheckTokenEndpointUrl(
        "http://localhost:8280/auth/realms/demo-realm/protocol/openid-connect/token/introspect");
    tokenServices.setClientId("demo-client");
    tokenServices.setClientSecret("80e19056-7770-4a4a-a3c4-06d8ac8792ef");
    tokenServices.setAccessTokenConverter(new KeycloakAccessTokenConverter());
    resources.tokenServices(tokenServices);

}
private class KeycloakAccessTokenConverter extends DefaultAccessTokenConverter {

    @Override
    public OAuth2Authentication extractAuthentication(Map<String, ?> map) {
        OAuth2Authentication oAuth2Authentication = super.extractAuthentication(map);
        Collection<GrantedAuthority> authorities = (Collection<GrantedAuthority>) oAuth2Authentication.getOAuth2Request().getAuthorities();
        if (map.containsKey("realm_access")) {
            Map<String, Object> realm_access = (Map<String, Object>) map.get("realm_access");
            if(realm_access.containsKey("roles")) {
                ((Collection<String>) realm_access.get("roles")).forEach(r -> authorities.add(new SimpleGrantedAuthority(r)));
            }
        }
        return new OAuth2Authentication(oAuth2Authentication.getOAuth2Request(),oAuth2Authentication.getUserAuthentication());
    }
}