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字符串序列化单元测试失败

junit serialization string java

Salem Masoud · 技术社区 · 6 年前

在运行JUnit测试之后 String 序列化失败,结果如下:

预期: "netmodel"
实际: "l"

序列化方法如下

public static void serializeString(String objectToSerialize, OutputStream outputStream) {
    byte[] bytesArr = objectToSerialize.getBytes();
    serializeInt(bytesArr.length, outputStream);
    try {

        outputStream.write(bytesArr);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

我的反序列化方法如下

public static String deserializeString(InputStream inputStream) {
String deserializeObject = "";
char asciiToChar;
int stringByteArrayLength = deserializeInt(inputStream);
byte[] databytesArr = new byte[stringByteArrayLength];

try {
  inputStream.read(databytesArr, 0, stringByteArrayLength);
}
catch (IOException e) {
  e.printStackTrace();
}

for (int i = 0; i < databytesArr.length; i++) {
  asciiToChar = (char) databytesArr[i];
  deserializeObject = "" + Character.toString(asciiToChar);
}
return deserializeObject;
}

最后,我编写了一个单元测试,如下所示

public class StringSerializerTest {

  private InputStream iStream;
  private ByteArrayOutputStream oStream;

  @Before
  public void init() {
    oStream = new ByteArrayOutputStream();
  }

  String serialzeAndDeserializeObject(String stringValue) {
    OutputStreamUtil.serializeString(stringValue, oStream);
    iStream = new ByteArrayInputStream(oStream.toByteArray());
    return InputStreamUtil.deserializeString(iStream);
  }

  @Test
  public void equals_equal() {
    String stringValue = "netmodel";
    String deserializedStringValue = serialzeAndDeserializeObject(stringValue);
    assertThat(deserializedStringValue).isEqualTo(stringValue);
  }
}

怎么了?如何修复?

2 回复 | 直到 6 年前

Justin Albano 6 年前

deserializeObject

for (int i = 0; i < databytesArr.length; i++) {
    asciiToChar = (char) databytesArr[i];
    deserializeObject = "" + Character.toString(asciiToChar);
}

l

for (int i = 0; i < databytesArr.length; i++) {
    asciiToChar = (char) databytesArr[i];
    deserializeObject += Character.toString(asciiToChar);
}

public static String deserializeString(InputStream inputStream) {
    String deserializeObject = "";
    char asciiToChar;
    int stringByteArrayLength = deserializeInt(inputStream);
    byte[] databytesArr = new byte[stringByteArrayLength];

    try {
        inputStream.read(databytesArr, 0, stringByteArrayLength);
    }
    catch (IOException e) {
        e.printStackTrace();
    }

    for (int i = 0; i < databytesArr.length; i++) {
        asciiToChar = (char) databytesArr[i];
        deserializeObject += Character.toString(asciiToChar);
    }
    return deserializeObject;
}

Joop Eggen 6 年前

DataOutputStream

public static void serializeString(String objectToSerialize, OutputStream outputStream)
        throws IOException {
    byte[] bytesArr = objectToSerialize.getBytes(StandardCharsets.UTF_8);
    serializeInt(bytesArr.length, outputStream);
    outputStream.write(bytesArr);
}

public static String deserializeString(InputStream inputStream)
        throws IOException {
    int stringByteArrayLength = deserializeInt(inputStream);
    byte[] databytesArr = new byte[stringByteArrayLength];
    readFully(inputStream, databytesArr);
    return new String(databytesArr, StandardCharsets.UTF_8);
}

private static void readFully(InputStream inputStream, byte[] bytes) throws IOException {
    int i = 0;
    while (i < bytes.length) {
        int nread = inputStream.read(bytes, i, bytes.length - i);
        if (nread <= 0) {
            throw new IOException("Premature EOF");
        }
        i += nread;
    }
}