无论如何,我考虑到了这个策略,稍微重构了您的代码,并且在每次单击add按钮时更好地处理当前索引。最新索引保存在表中的数据属性中。
$("#addBtn").click(function(){
const latestIndex = $('#exampleTable').data('latest-index');
let i = latestIndex+1;
const newRow = $('#trid1').clone();
newRow.prop('id', `trid${i}`);
newRow.data('index', i);
newRow.text(i);
newRow.appendTo('table#exampleTable > tbody');
$('#exampleTable').data('latest-index', i);
});
button{
cursor: pointer;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table class="table" id="exampleTable" data-latest-index="1">
<thead>
<tr>
<th scope="col">Rows</th>
</tr>
</thead>
<tbody>
<tr id="trid1" class="trclass">
<th scope="row">1</th>
</tr>
</tbody>
</table>
<button type="button" id="addBtn">Add</button>