python中值处的切片(未排序)数组

1. 那是个好主意 list

2. 尝试

   >>> a = [1,1,2,3,5,8,13,21]
   >>> import itertools
   >>> for x in itertools.takewhile(lambda val: val != 8, a):
   ...     print x
   ...
   1
   1
   2
   3
   5
   

假设数组已排序,请使用二进制搜索。函数位于 bisect module .

from bisect import bisect_right
a[:bisect_right(a, value)]

创建一个生成器,并使用它:

a = [1,1,2,3,5,8,13,21]

def _gen(listing, cutoff):
    for i in listing:
        if i == cutoff:
            return

        yield i

new_a = list(_gen(a, 5))

for i, val in enumerate(a):
    if val == cutoff:
        break

new_a = a[:i]