代码之家 › 专栏 › 技术社区 › rollsch

通过两列的SQL EG Group生成每个客户每月的销售报告,并将第三列相加

azure-sql-server join sql-server sql

-1

rollsch · 技术社区 · 6 年前

我很少编写SQL(AzureSQL),但是我尝试生成每个客户每月的销售总额。

顾客:

    |Username     |ID    |
    |user1        |1     |
    |user2        |2     |
    |user3        |3     |

秩序:

    |CustomerId   |Month |Total     |
    |1            |1     |275       |
    |1            |1     |10        |
    |2            |1     |100       |
    |1            |3     |150       |
    |2            |2     |150       |
    |2            |2     |65        |
    |3            |2     |150       |

我想生产

|Username     |Month1Total |Month2Total | Month3Total |
|user1        |285         |275         |     150     |
|user2        |100         |215         |      0      |
|user3        |0           |150         |      0      |

我可以做以下事情

SELECT customerTable.Username Username, SUM(orderTable.OrderTotal) TotalMay
FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id
WHERE DATENAME(Month, (orderTable.PaidDateUTC)) = 'May'
GROUP BY Username

这将给我每月的产量。但是我不知道如何循环这个,每月执行一次,然后按用户名分组。

4 回复 | 直到 6 年前

Anonymous 6 年前

如果您希望每个月都有一个单独的列,请尝试此操作

SELECT customerTable.Username Username
,SUM(iif(ordertable.[month] = 1,orderTable.OrderTotal,0)) TotalJan
,SUM(iif(ordertable.[month] = 2,orderTable.OrderTotal,0)) TotalFeb
,SUM(iif(ordertable.[month] = 3,orderTable.OrderTotal,0)) TotalMar
,SUM(iif(ordertable.[month] = 4,orderTable.OrderTotal,0)) TotalApr
,SUM(iif(ordertable.[month] = 5,orderTable.OrderTotal,0)) TotalMay

FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id

GROUP BY Username

应该很容易添加剩余月份

Zaynul Abadin Tuhin 6 年前

你可以在什么时候使用案例

  with t1 as
   ( select o.CustomerId,o.Month, sum(Total) as total from
      [Order] 
     group by o.CustomerId,o.Month
  ) select c.Username, 
   case when t1.month=1 then t1.total else 0 end month1,
   case when t1.month=2 then t1.total else 0 end month2,
   case when t1.month=3 then t1.total else 0 end month3 
   from t1 join Customer c on t1.CustomerId=c.ID

或者可以使用Pivot

select c.username, t.* from
(
select * from 
(select * from ord
) src
pivot
( sum(Total) FOR Month IN ([1],[2],[3])
) pvt
) as t join Customer c on t.CustomerId=c.ID

MJH 6 年前

像这样:

SELECT DATENAME(Month, (orderTable.PaidDateUTC)) MonthName, 
   customerTable.Username Username, 
   SUM(orderTable.OrderTotal) TotalMay
FROM "Order" orderTable
JOIN Customer customerTable ON orderTable.CustomerId = customerTable.Id
GROUP BY DATENAME(Month, (orderTable.PaidDateUTC)), Username

您只需要将月份名称从WHERE子句移到GROUPBY。

Yogesh Sharma 6 年前

我就这么做 JOIN 使用条件聚合:

SELECT c.Username, 
       SUM(CASE WHEN o.Month = 1 THEN o.Total ELSE 0 END) AS [Month1Total],
       SUM(CASE WHEN o.Month = 2 THEN o.Total ELSE 0 END) AS [Month2Total],
       SUM(CASE WHEN o.Month = 3 THEN o.Total ELSE 0 END) AS [Month3Total],
       . . . 
FROM Customer C INNER JOIN
     Order o
     ON o.CustomerId = c.id
GROUP BY c.Username;