Cakephp中的并集语法

太多的程序员试图将自己局限于框架的功能。不要。使用框架提供的。如果它没有您想要的功能,那么:

• 将所需的功能编码到类扩展中

• 自定义在框架内旋转代码以满足您的需要。

Complex Find Conditions 找到了你的答案:

$joins = array(
    array(
        'table' => 'test_twos',
        'alias' => 'TestTwo',
        'type' => 'LEFT',
        'conditions' => array(
            'TestTwo.id = TestOne.id',
        )
    ),
    array(
        'table' => 'test_threes',
        'alias' => 'TestThree',
        'type' => 'LEFT',
        'conditions' => array(
        'TestThree.id = TestOne.id',
    )
    )
);

$dbo = $this->getDataSource();
$subQuery = $dbo->buildStatement(
    array(
        'fields' => array('*'),
        'table' => $dbo->fullTableName($this),
        'alias' => 'TestOne',
        'limit' => null,
        'offset' => null,
        'joins' => $joins,
        'conditions' => null,
        'order' => null,
        'group' => null
    ),
    $this->TestOne
);
$query = $subQuery;

$query .= ' UNION ';
$joins = array(
    array(
        'table' => 'test_twos',
        'alias' => 'TestTwo',
        'type' => 'LEFT',
        'conditions' => array(
            'TestTwo.id = TestOne.id',
        )
    ),
    array(
        'table' => 'test_threes',
        'alias' => 'TestThree',
        'type' => 'RIGHT',
        'conditions' => array(
        'TestThree.id = TestOne.id',
        )
    )
);

$dbo = $this->getDataSource();
$subQuery = $dbo->buildStatement(
    array(
    'fields' => array('*'),
    'table' => $dbo->fullTableName($this),
    'alias' => 'TestOne',
    'limit' => null,
    'offset' => null,
    'joins' => $joins,
    'conditions' => null,
    'order' => null,
    'group' => null
    ),
    $this->TestOne
);

$query .= $subQuery;

pr($query);

http://dev.mysql.com/doc/refman/5.6/en/create-view.html . 您还可以使用像HeidiSQL这样的软件来帮助您创建视图。

你的模型中会有这样的东西:

class Contenu extends AppModel {
    public $useTable = 'v_contenu';

这允许您仍然使用 find() CakePHP中的方法,非常好。

使用视图,然后从中选择:

create view my_union as
SELECT * FROM t1
LEFT JOIN t2 ON t1.id = t2.id
LEFT JOIN t3 ON t2.id = t3.id
UNION
SELECT * FROM t1
RIGHT JOIN t2 ON t1.id = t2.id
LEFT JOIN t3 ON t2.id = t3.id
UNION
SELECT * FROM t1
RIGHT JOIN t2 ON t1.id = t2.id
RIGHT JOIN t3 ON t2.id = t3.id

在代码中:

select * from my_union

使用如下代码:

$friendsPosts= $this->Posts->find('all')
                ->contain(['Users', 'Languages', 'PostStates'])
                ->innerJoinWith('Users.Dusers', function ($q) {
                    return $q->where(['Dusers.id' => $this->Auth->user('id')]);
                });

        $posts= $this->Posts->find('all')
                ->where(['Posts.post_state_id' => 3])
                ->contain(['Users', 'Languages', 'PostStates']);

    $posts->union($friendsPosts);