如何使用PIL(Python Imaging)反转图像的颜色?

从文档中尝试以下操作: http://effbot.org/imagingbook/imageops.htm

from PIL import Image
import PIL.ImageOps    

image = Image.open('your_image.png')

inverted_image = PIL.ImageOps.invert(image)

inverted_image.save('new_name.png')

如果图像是RGBA透明的这将失败。。。不过,这应该是可行的:

from PIL import Image
import PIL.ImageOps    

image = Image.open('your_image.png')
if image.mode == 'RGBA':
    r,g,b,a = image.split()
    rgb_image = Image.merge('RGB', (r,g,b))

    inverted_image = PIL.ImageOps.invert(rgb_image)

    r2,g2,b2 = inverted_image.split()

    final_transparent_image = Image.merge('RGBA', (r2,g2,b2,a))

    final_transparent_image.save('new_file.png')

else:
    inverted_image = PIL.ImageOps.invert(image)
    inverted_image.save('new_name.png')

对于在“1”模式下处理图像的任何人(即1位像素,黑白,每字节存储一个像素)-- see docs PIL.ImageOps.invert

因此:

im = im.convert('L')
im = ImageOps.invert(im)
im = im.convert('1')

以防有人把 CMYK 如图所示,当前的PIL和Pillow实现似乎不支持这一点,并抛出了一个错误。然而,您可以通过使用这个方便的函数(基本上是Greg Sadetsky上面文章的扩展)反转图像的各个波段,轻松地绕过这个问题:

def CMYKInvert(img) :
    return Image.merge(img.mode, [ImageOps.invert(b.convert('L')) for b in img.split()])

from PIL import Image

img = Image.open("archive.extension") 

pixels = img.load()

for i in range(img.size[0]):
    for j in range(img.size[1]):
        x,y,z = pixels[i,j][0],pixels[i,j][1],pixels[i,j][2]
        x,y,z = abs(x-255), abs(y-255), abs(z-255)
        pixels[i,j] = (x,y,z)

img.show()