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如何给出错误而不是系统错误[重复]

int numbers error-handling string python

-1

bot_diyar · 技术社区 · 6 年前

嘿,我在python3中有了我的数字猜测器。但是如果用户键入字母而不是数字,我想给出一个错误。当我打一封信时,上面写着

Traceback (most recent call last):
  File "nummerlol.py", line 14, in <module>
    guess = int(guess)
ValueError: invalid literal for int() with base 10:"

是否有方法更改此错误?thx公司

import time
import random 
from secrets import randbelow
guesscount = 0
print("Hey whats your name")
name = input()
number = randbelow(20)
print("The Number is between 1 & 20")
while guesscount < 6:
    print("Guess.")
    guess = input()
    guess = int(guess)
    guesscount = guesscount + 1
    if guess < number:
        print("My Number is bigger")
    if guess > number:
        print("My Number is lower")
    if guess == number:
        break
if guess == number :
guesscount = str(guesscount)
print("Nice",name ,".")
print("You needed" ,guesscount ,"Tries")
if guess != number:
    number = str(number)
    print("Bruh,My Number was" ,number)`

2 回复 | 直到 6 年前

RuthC 6 年前

您可以使用“尝试除外”循环。具有 continue (如下)用户可以继续猜测。您还可以将自己的异常替换为 print 和 持续 如果您希望脚本以更具信息性的消息中断。

import time
import random 
from secrets import randbelow
guesscount = 0
print("Hey whats your name")
name = input()
number = randbelow(20)
print("The Number is between 1 & 20")
while guesscount < 6:
    print("Guess.")
    guess = input()
    try:
        guess = int(guess)
    except:
        print("That is not a number")
        continue
    guesscount = guesscount + 1
    if guess < number:
        print("My Number is bigger")
    if guess > number:
        print("My Number is lower")
    if guess == number:
        break
if guess == number :
    guesscount = str(guesscount)
print("Nice",name ,".")
print("You needed" ,guesscount ,"Tries")
if guess != number:
    number = str(number)
    print("Bruh,My Number was" ,number)

Tasha R 6 年前

A. similar question 你的问题已经存在了,但我还是会回答你的问题。

正如您所知,您得到回溯响应的原因是因为您试图在调用时将非整数转换为整数 int(guess) 。可以使用try/except块捕获此异常。例如,您可以用以下代码替换有问题的代码行:

while True:
  try:
    guess = int(guess)
    break
  except ValueError:
    print("You must enter a valid number.")

此代码将导致程序要求用户输入,直到该输入有效。看看这条蟒蛇3 handling errors and exceptions 有关详细信息,请参阅文档。