相继使用的getline和cin跳过下一个输入

我正在编写一个C++程序来演示聚合概念,作为一本书中的示例。该代码由4个类(在一个文件中)和一个主函数(在另一个文件)组成。 课程如下

#include <iostream>
#include <string>
/*#define  SYNC_CLEAR {\
                    cin.clear();\
                    cin.sync();\
                }
*/
using std::string;
using std::cout;
using std::cin;

class Student
{
private:
    string school;
    string degree;
public:
    void input_data()
    {
        cout<<"Enter School name and degree name \n";
        getline(cin,school);
        getline(cin,degree);
    }
    void show_data() const
    {
        cout<<"School :"<<school<<",Degree: "<<degree<<"\n";
    }

};

class Employee
{
private:
    string name;
    unsigned int number;
public:
    void input_data()
    {
        string str;
        cout<<"Enter Name and number \n";
        getline(cin,name);
        cin>>number;
    }
    void show_data() const
    {
        cout<<"Name :"<<name<<",number: "<<number<<"\n";
    }
};


/************************Aggregation starts from here**********************************/
class Manager
{
private:
    string title;
    double dues;
    Employee emp;   // object of one class as an attribute to other class
    Student stu;    // object of one class as an attribute to other class
public:
    **void input_data()
    {
        emp.input_data();   // call by object of Employee class
        cout<<"Enter Title and Dues \n";
        /*********Problem comes here*****************/
        getline(cin,title);
        cin>>dues;
        /**************************/
        stu.input_data();   // call by object of Student class
    }**
    void show_data() const
    {
        emp.show_data();
        cout<<"Title :"<<title<<",Dues: "<<dues<<"\n";
        stu.show_data();
    }   
};

class Scientist
{
private:
    int pubs;
    Employee emp;   // object of one class as an attribute to other class
    Student stu;    // object of one class as an attribute to other class
public:
    void input_data()
    {
        emp.input_data();   // call by object of Employee class
        cout<<"Enter no of pubs \n";
        cin>>pubs;
        stu.input_data();   // call by object of Student class
    }
    void show_data() const
    {
        emp.show_data();
        cout<<" pubs :"<<pubs<<"\n";
        stu.show_data();
    }   
};

主要功能如下:

#include <iostream>
#include "aggregation.h"

using std::cout;
using std::cin;

int main(int argc, char const *argv[])
{
    Manager m1;
    Scientist s1,s2;
    cout<<"Data for Manager\n";
    m1.input_data();

    cout<<"Data for Sci 1\n";
    s1.input_data();

    cout<<"Data for Sci 2\n";
    s2.input_data();

    cout<<"Data for Manager\n";
    m1.show_data();

    cout<<"Data for Sci 1\n";
    s1.show_data();

    cout<<"Data for Sci 2\n";
    s2.show_data();

    return 0;
}

问题出现在input_data()函数中的类管理器中(以粗体突出显示)

hduser@M-1939:~/Dropbox/c++/lafore/inhertiance$ g++ -g aggregation.cpp -o aggregation
hduser@M-1939:~/Dropbox/c++/lafore/inhertiance$ ./aggregation 
Data for Manager
Enter Name and number 
vivek 
100
***Enter Title and Dues 
sr manager***
Enter School name and degree name 
Data for Sci 1
Enter Name and number 
Enter no of pubs 
Enter School name and degree name 
Data for Sci 2
Enter Name and number 
Enter no of pubs 
Enter School name and degree name 
Data for Manager
Name :vivek,number: 100
Title :,Dues: 0
School :,Degree: 
Data for Sci 1
Name :,number: 6299824
 pubs :6299824
School :,Degree: 
Data for Sci 2
Name :,number: 2092888488
 pubs :6299112
School :,Degree: 

我看了一些使用cin的链接。clear()和cin。sync(),但它也不起作用。有问题,不是这样,不同,但仍然是类似的问题。 有线索吗?

编辑1: 我使用将输入序列从1:getline2:cin更改为1:cin2:cin。ignore()3:getline,它正在工作。但有人能告诉我怎么做吗?为什么它不能以以前的方式工作。

编辑2:我忘了放cin。cin之后的ignore()>>Employee类的input_data()中的数字。它起作用了吗。虽然这是个愚蠢的错误。