我如何无法从DB行附加到拆分的字符串文件名(我需要“mode=2”和“case 2:”)。
在我的日志文件错误:
要附加的文件错误:找不到文件
'C:\inetpub\wwwroot\PlatTFORM_700_NTFSRV\PlatTFORM_700_NTFSRV_LAB\Attachments\text.txt,text2.txt'。
这里是我的示例代码和DB中的行
数据库中的行:
|FILE_TO_ATTACH |
|text1.txt,text2.txt|
public DataTable GetAttachmentFiles(int mode , string fileIDList)
{
try
{
DataTable DTB = new DataTable();
if (mode == 1)
{
SqlCommand TheCommand = GetCommand("application_MessageAttachFiles", CommandType.StoredProcedure,
GetConnection("APP"));
TheCommand.Parameters.Add("FILEIDLIST", SqlDbType.VarChar, 8000);
TheCommand.Parameters["FILEIDLIST"].Value = fileIDList;
SqlDataAdapter SDA = new SqlDataAdapter();
SDA.SelectCommand = TheCommand;
SDA.Fill(DTB);
}
else if(mode == 2)
{
try
{
DTB.Columns.Add("FILENAME");
string[] fileList = fileIDList.Split(',');
for (int c = 0; c < fileList.Length; c++)
{
DataRow DR = DTB.NewRow();
DR["FILENAME"] = fileList[c];
DTB.Rows.Add(DR);
}
}
catch (Exception ex)
{
RecordLine("ERROR Reading GetAttachmentFiles: " + ex.Message);
}
}
return DTB;
}
catch (Exception eX)
{
RecordLine("ERROR GetAttachmentFiles : " + eX.Message);
return null;
}
}
public Attachment AttachmentFile(int mode, string fileNameString, int fileID, DataRow DRA)
{
// mode.ToString(ConfigurationSettings.AppSettings["MODE"]);
try
{
switch (mode)
{
case 1: /*from Database*/
if (DRA != null)
{
Attachment messageAttachment;
int fileDataSize = int.Parse(DRA["FileSize"].ToString());
string fileType = DRA["FileType"].ToString();
string fileName = DRA["FileName"].ToString();
byte[] fileBuffer = (DRA["FileData"]) as byte[];
MemoryStream ms = new MemoryStream(fileBuffer);
RecordLine("DEBUG 2 - " + fileName + " " + fileType + " " + fileDataSize.ToString() + " " + ms.Length.ToString() + " buffer size:" + fileBuffer.Length.ToString());
messageAttachment = new Attachment(ms, fileName, fileType);
return messageAttachment;
}
break;
case 2: /*from Local Machin */
{
Attachment messageAttachment;
try
{
fileNameString = String.Format("{0}\\{1}", ConfigurationSettings.AppSettings["SOURCE_FILE"],
fileNameString);
messageAttachment = new Attachment(fileNameString);
RecordLine("DEBUG 2.1 - " + messageAttachment.Name);
return messageAttachment;
}
catch (Exception ex)
{
RecordLine("FILE TO ATTACH ERR : " + ex.Message);
}
}
break;
default:
return null;
break;
}
return null;
}
catch (Exception eX)
{
RecordLine("ERROR AttachmentFile : " + eX.Message);
return null;
}
}