试试这个自定义合并逻辑。
def find_missing_items_in_arr(arr1, arr2)
arr1_size = arr1.size
arr2_size = arr2.size
if (arr1_size == arr2_size) && (arr1 & arr2).size == arr1_size
return [] # Same array
end
arr2 - arr1
end
def custom_merge(target_hash, source_hash)
# If you want to preserve frozen state of entries, please use `clone`
duped_target_hash = target_hash.dup
source_hash.each do |k, v|
unless duped_target_hash.key?(k)
duped_target_hash[k] = v
next
end
case v
when Array
missing_items_in_arr = find_missing_items_in_arr(duped_target_hash[k], v)
if missing_items_in_arr.size > 0
duped_target_hash[k] += missing_items_in_arr
end
when Hash
duped_target_hash[k] = custom_merge(duped_target_hash[k], v)
else
# Nothing to do here
end
end
duped_target_hash
end
用法
one = {
"endpoints"=>["get_route"],
"features"=>["channel_selection"],
"get_route"=> {
"output"=> ["total_length", "seca_length"],
"options"=> ["panama", "abcd"]
}
}
other = {
"endpoints"=>["get_route"],
"features"=>["channel_selection"],
"get_route"=> {
"output"=> ["total_length", "seca_length"],
"options"=> ["panama", "suez", "kiel"]
}
}
rs_hash = custom_merge(other, one)
puts rs_hash
注意
:rails提供
deep_merge
但这可以在铁轨外使用。我已经测试过了,它会返回你想要的输出。它还处理更多的嵌套条目,如
one = {
"endpoints"=>["get_route"],
"features"=>["channel_selection"],
"get_route"=> {
"output"=> ["total_length", "seca_length"],
"options"=> ["panama", "abcd"],
"custom_options" => {
"custom_output" => ["abc"],
"custom_input" => ["xyz" ]
}
}
}
other = {
"endpoints"=>["get_route"],
"features"=>["channel_selection"],
"get_route"=> {
"output"=> ["total_length", "seca_length"],
"options"=> ["panama", "suez", "kiel"],
"custom_options" => {
"custom_output" => ["abc", "def"]
}
}
}
希望这有帮助。