扩展typescript接口+优化函数签名

是否可以定义一个对象接口,然后扩展接口,细化方法签名?

我想和这个一起工作 strictFunctionTypes true .

interface Plugin {
    addListener: (eventName: string) => void;
}

interface FooPlugin extends Plugin {
    addListener: (eventName: 'fooChanged') => void;
}

这里我得到以下错误:

Interface 'FooPlugin' incorrectly extends interface 'Plugin'.
    Types of property 'addListener' are incompatible.
        Type '(eventName: "fooChanged") => void' is not assignable to type '(eventName: string) => void'.
            Types of parameters 'eventName' and 'eventName' are incompatible.
                Type 'string' is not assignable to type '"fooChanged"'.

下面是一个更复杂的例子,展示了我最终想要做的事情:

export interface Plugin {
    addListener: (eventName: string, fn: Function) => void;
}

export interface FooPlugin extends Plugin {
    addListener: (eventName: 'fooInit', fn: (n: { i: boolean }) => void) => void;
    addListener: (eventName: 'fooDestroy', fn: (n: { d: number }) => void) => void;
}