通过`.join格式化不一致消息时出现问题`

请尝试下面的代码,它不是一个单行程序,但我想它更具可读性

userid = ['User 1 ID', 'User 2 ID', 'User 3 ID']
name = ['User 1 Name', 'User 2 Name', 'User 3 Name']
discriminator = ['User 1 Disc', 'User 2 Disc', 'User 3 Disc']

total = list((zip(userid, name, discriminator)))

# reformat the code into the desired formatting
pretty_list = set()
for details in total:
    data = "•<@{} ({}#{})>".format(details[0], details[1], details[2]) 
    pretty_list.add(data)

# debug print below
# print("**Ban list:** \n{}".format("\n".join(pretty_list)))

await client.send_message(message.channel, "**Ban list:** \n{}".format("\n".join(pretty_list)))

好运:)

您可以尝试以下代码:

userid = ['User 1 ID', 'User 2 ID', 'User 3 ID']
name = ['User 1 Name', 'User 2 Name', 'User 3 Name']
discriminator = ['User 1 Disc', 'User 2 Disc', 'User 3 Disc']

total = zip(userid, name, discriminator)

await client.send_message(message.channel, "**Ban List:** \n{}".format("\n".join(["• {}".format(" ".join(list(item))) for item in total])))

这里有一个单列(ish)解决方案:

userid = ['User 1 ID', 'User 2 ID', 'User 3 ID']
name = ['User 1 Name', 'User 2 Name', 'User 3 Name']
discriminator = ['User 1 Disc', 'User 2 Disc', 'User 3 Disc']

#convert [['a1', 'a2'], ['b1', 'b2']] to iter([('a1', 'b1'), ('a2', 'b2')])
total = zip(userid, name, discriminator)

await client.send_message(message.channel, "**Ban List:**\n"
                          + "\n".join("• {} ({}#{})".format(*i) for i in total))

输出应为:

禁止名单:

用户1 ID(用户1名称#用户1光盘)

–User 2 ID(User 2 Name#User 2光盘)

用户3 ID(用户3名称#用户3光盘)