基于redux状态有条件地调用组件中的函数的方式和位置

我有一个组件,在我的组件中我有一些子组件。

在父组件中,我有一些函数,我想从子组件触发它。所以我和雷德克斯一起去。

它是我的父组件:

   import React, { Component } from "react";
    import { withRouter } from "react-router-dom";
    import { bindActionCreators } from "redux";
    import { splashStop } from "store/actions/Home/splashStop";

import { connect } from "react-redux";

class Home extends Component {
  constructor(props) {
    super(props);
    this.state = {
    };
    this.goPage = this.goPage.bind(this);
  }

  componentDidMount() {
  }

  goPage = () => {
     this.props.history.push("/agencies");
  };

  render() {
    if (this.props.homeSplash.splashStart == true) {
      myTime.play();
    }
    return (
      <div>
         <ChildComponent />
      </div>
    );
  }
}

const mapStateToProps = state => ({
  homeSplash: state.homeSplash
});

function mapDispatchToProps(dispatch) {
  return {
    splashStop: bindActionCreators(splashStop, dispatch)
  };
}

export default connect(
  mapStateToProps,
  mapDispatchToProps
)(withRouter(Home));

这是我的孩子部分:

下面是我在onClick函数的子组件中分派redux操作:

  triggerSplash = () => {
    this.props.splashStart();
  };

我的行动:

导出const START_SPLASH= “开始飞溅”;

export const splashStart = () => {
    return dispatch => {
        dispatch({
            type: START_SPLASH,
            payload: true
          });
    };
  };

还有我的减速机:

import { START_SPLASH } from "store/actions/Home/splashStart";

let initialState = {
  splashStart: false
};

export default (state = initialState, action) => {
  switch (action.type) {
    case START_SPLASH:
      return { ...state, splashStart: action.payload };
    default:
      return state;
  }
};

我的减速器,动作正常。

我在想为什么 myTime.play(); 总是在组件安装时工作,只是不关心此控件:

if (this.props.homeSplash.splashStart == true) {
          myTime.play();
        }

我放错地方了还是怎么了?