如何使用Python中的索引从列表中提取元素?

也许可以使用这个:

[a[i] for i in (1,2,5)]
# [11, 12, 15]

我想你在找这个:

elements = [10, 11, 12, 13, 14, 15]
indices = (1,1,2,1,5)

result_list = [elements[i] for i in indices]    

尝试

numbers = range(10, 16)
indices = (1, 1, 2, 1, 5)

result = [numbers[i] for i in indices]

使用numpy直接数组索引,如matlab,julia,…

a = [10, 11, 12, 13, 14, 15];
s = [1, 2, 5] ;

import numpy as np
list(np.array(a)[s])
# [11, 12, 15]

更好的是,只需使用numpy数组

a = np.array([10, 11, 12, 13, 14, 15])
a[s]
#array([11, 12, 15])

检查边界:

 [a[index] for index in (1,2,5,20) if 0 <= index < len(a)]
 # [11, 12, 15]